imagecreatefromjpeg() php
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imagecreatefromjpeg() php
提问by Anurag
I'm using imagecreatefromjpeg() function to merge two pictures..
我正在使用 imagecreatefromjpeg() 函数来合并两张图片..
now the problem which I'm facing is that when I use the pictures from my server, it works perfectly and when I use pictures from some other website, it doesn't work.
现在我面临的问题是，当我使用服务器上的图片时，它运行良好，而当我使用其他网站的图片时，它不起作用。
For example: when I use this PHP file http://coolfbapps.in/test/merger.phpwith function
例如：当我使用这个 PHP 文件http://coolfbapps.in/test/merger.phpwith function
imagecreatefrompng('http://coolfbapps.in/test/1.png');
It works perfectly fine as the image is at my own server
它工作得很好，因为图像在我自己的服务器上
but when I alter this function n put the link of an image which is not on my server,
但是当我改变这个函数时，把一个不在我的服务器上的图像的链接，
for example.
例如。
imagecreatefrompng('http://www.businesseconomics/Test.png');
it doesnt work. (the image file is not on my server)
它不起作用。（图像文件不在我的服务器上）
please suggest me an alternative to this function or a solution as I want to use this with Facebook apps..
请给我建议此功能的替代方案或解决方案，因为我想将其与 Facebook 应用程序一起使用。
Functions like file-get-contents are also showing the same error. I hope its not server end problem.. allow_url_fopen is on but allow_url_include is off
file-get-contents 等函数也显示相同的错误。我希望它不是服务器端问题..allow_url_fopen 已打开但 allow_url_include 已关闭
Update...Actual code. I'm using this to merger two pictures
更新...实际代码。我正在用它来合并两张图片
$dest = imagecreatefrompng('http://coolfbapps.in/test/1.png');
$src = imagejpeg('http://img.allvoices.com/thumbs/image/111/111/75152279-pic.jpg');
imagealphablending($dest, false);
imagesavealpha($dest, true);
imagecopymerge($dest, $src, 10, 9, 0, 0, 181, 180, 100);
header('Content-Type: image/png');
imagepng($dest);
imagedestroy($dest);
imagedestroy($src);
回答by Mark Mooibroek
Instead of using file_get_contentyou can use cURLto get your image data. Here is a resource:
http://php.net/manual/en/book.curl.php
而不是使用file_get_content您可以使用cURL来获取您的图像数据。这是一个资源：http:
//php.net/manual/en/book.curl.php
Example with getting html ( images will also work ):
获取 html 的示例（图像也可以）：
<?php
$ch = curl_init("http://img.allvoices.com/thumbs/image/111/111/75152279-pic.jpg");
$fp = fopen("example_homepage.jpg", "w");
curl_setopt($ch, CURLOPT_FILE, $fp);
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_exec($ch);
curl_close($ch);
fclose($fp);
$img = imagecreatefromjpeg("example_homepage.jpg");
?>
回答by alex
Sounds like the function does not have URL opening capabilities, or it does and you have allow_url_fopenoff in php.ini. You can't use ini_set()for security reasons.
听起来该功能没有 URL 打开功能，或者它有，而您allow_url_fopen在php.ini. ini_set()出于安全原因，您不能使用。
You could download the file to your local server, and then open it.
您可以将文件下载到本地服务器，然后打开它。
file_put_contents('image.jpg',
file_get_contents('http://www.businesseconomics/Test.png')
);
You could probably use copy()too, the docs hint that it can read URLs.
您也可以使用copy()，文档提示它可以读取 URL。
回答by Santosh Linkha
Something like this might help.
像这样的事情可能会有所帮助。
$imagestr = file_get_contents('http://www.businesseconomics/Test.png');
$image = imagecreatefromstring($imagestr);
imagecreatefrompng($image);
UPDATED::
更新::
$imagestr = file_get_contents('http://www.gravatar.com/avatar/95111e2f99bb4b277764c76ad9ad3569?s=32&d=identicon&r=PG');
$image = imagecreatefromstring($imagestr);
header('Content-type: image/jpeg');
imagejpeg($image);
