在 PHP < 5.3 中从时间戳创建日期时间
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Creating DateTime from timestamp in PHP < 5.3
提问by Yarin
How do you create a DateTime from timestamp in versions less than < 5.3?
在小于 5.3 的版本中，如何从时间戳创建 DateTime？
In 5.3 it would be:
在 5.3 中，它将是：
$date = DateTime::createFromFormat('U', $timeStamp);
The DateTime constructor wants a string, but this didn't work for me
DateTime 构造函数需要一个字符串，但这对我不起作用
$date = new DateTime("@$timeStamp");
回答by Dawid Ohia
PHP 5 >= 5.3.0
PHP 5 >= 5.3.0
$date = new DateTime();
$date->setTimestamp($timeStamp);
Edit:Added correct PHP version for setTimestamp
编辑：添加了正确的 PHP 版本setTimestamp
回答by Barry Simpson
Assuming you want the date and the time and not just the date as in the previous answer:
假设您想要日期和时间，而不仅仅是上一个答案中的日期：
$dtStr = date("c", $timeStamp);
$date = new DateTime($dtStr);
Seems pretty silly to have to do that though.
不过，必须这样做似乎很愚蠢。
回答by Jonah
It's not working because your $timeStamp variable is empty. Try echoing the value of $timeStamp right before creating the DateTime and you'll see. If you run this:
它不起作用，因为您的 $timeStamp 变量为空。在创建 DateTime 之前尝试回显 $timeStamp 的值，您会看到。如果你运行这个：
new DateTime('@2345234');
You don't get an error. However, if you run:
你没有得到错误。但是，如果您运行：
new DateTime('@');
It produces the exact error you said it gives you. You'll need to do some debugging and find out why $timeStamp is empty.
它会产生您所说的确切错误。您需要进行一些调试并找出 $timeStamp 为空的原因。
回答by Yarin
The following works:
以下工作：
$dateString = date('Ymd', $timeStamp);
$date = new DateTime($dateString);
