如何在 bash 中使用 jq 创建 for 循环
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How to create for-loops with jq in bash
提问by crocefisso
I'm trying to split a json file into various json files. The input (r1.json) looks like :
我正在尝试将 json 文件拆分为各种 json 文件。输入 (r1.json) 看起来像：
{
"results" : [
{
content 1
}
,
{
content 2
}
,
{
content n
}
]
}
I'd like the output to be n files : 1.json, 2.json, n.json. Respectively containing {content 1}, {content 2} and {content n}.
我希望输出为 n 个文件：1.json、2.json、n.json。分别包含{content 1}、{content 2}和{content n}。
I tried :
我试过 ：
for i in {0..24}; do cat r1.json | jq '.results[$i]' >> $i.json; done
But I have the following error: error: i is not defined
但我有以下错误：错误：我没有定义
采纳答案by crocefisso
While the above answers are correct, note that interpolating shell variables in jq scripts is a terrible idea for all but the most trivial of scripts. On any of the solutions provided, replace the following:
虽然上述答案是正确的，但请注意，在 jq 脚本中插入 shell 变量对于除最微不足道的脚本之外的所有脚本来说都是一个糟糕的主意。在提供的任何解决方案上，替换以下内容：
jq ".results[$i]"
With the following:
具有以下内容：
jq --arg i "$i" '.results[$i | tonumber]'
回答by shellter
Try
尝试
for i in {0..24}; do cat r1.json | jq ".results[$i]" >> $i.json; done
Note that shell variables can't be expanded inside of single-quotes.
请注意，shell 变量不能在单引号内展开。
IHTH
IHTH
回答by Mad Physicist
The single quotes are probably what is messing you up. Bash variables are not expanded in single quotes. You are passing a literal string .results[$i]to jq. Try double quotes instead:
单引号可能是什么让你搞砸了。Bash 变量不在单引号中展开。您正在将文字字符串传递.results[$i]给jq. 试试双引号：
for i in {0..24}; do
cat r1.json | jq ".results[$i]" >> $i.json
done
