C++ 错误 - 编译 g++ 文件时“#include 需要“FILENAME”或 <FILENAME>”
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Error - "#include expects "FILENAME" or <FILENAME>" while compiling g++ file
提问by Singh
I'm quite new to Linux programming.
I'm compiling a simple C++ code using g++:
我对 Linux 编程很陌生。我正在使用以下命令编译一个简单的 C++ 代码g++：
#include“recip.hpp”
#include<cassert>
double recip (int i) {
// I should be non-zero.
assert (i != 0);
return 1.0/i;
}
The file recip.hppexists in my current directory. I don't understand why I'm getting an error:
该文件recip.hpp存在于我的当前目录中。我不明白为什么我收到错误：
recip.cpp:1:9: error: #include expects "FILENAME" or <FILENAME>
What's wrong?
怎么了？
回答by
The compiler is not a text editor, nor a human - it checks for exact character code match, not for visual similarity... You have to use
编译器不是文本编辑器，也不是人类 - 它会检查字符代码是否完全匹配，而不是视觉相似性......你必须使用
#include "recip.hpp"
using the standard double quotation marks.
使用标准的双引号。
回答by Jonathan Leffler
Your first line, treated as UTF-8, reads:
您的第一行被视为 UTF-8，内容如下：
0x23 = U+0023
0x69 = U+0069
0x6E = U+006E
0x63 = U+0063
0x6C = U+006C
0x75 = U+0075
0x64 = U+0064
0x65 = U+0065
0xE2 0x80 0x9C = U+201C
0x72 = U+0072
0x65 = U+0065
0x63 = U+0063
0x69 = U+0069
0x70 = U+0070
0x2E = U+002E
0x68 = U+0068
0x70 = U+0070
0x70 = U+0070
0xE2 0x80 0x9D = U+201D
0x0A = U+000A
The U+201C and U+201D need to be replaced by U+0022 (ASCII 34), or ".
U+201C 和 U+201D 需要替换为 U+0022 (ASCII 34) 或"。
MS Word and other word processors make bad editors for C code.
MS Word 和其他文字处理器为 C 代码编写了糟糕的编辑器。
回答by 22too
start swig when wei build example.i.
当wei构建example.i时开始swig。
example_wrap.c:2948:10: error: #include expects "FILENAME" or
example_wrap.c:2948:10: 错误：#include 需要“FILENAME”或
/* File: example.i */
%module example
%{
#define SWIG_FILE_WITH_INIT
#include 'example.h'
%}
int fact(int n);
we change code :
我们更改代码：
/* File: example.i */
%module example
%{
#define SWIG_FILE_WITH_INIT
#include "example.h"
%}
int fact(int n);
it is just in include 'double quote'.
它只是包含“双引号”。
