php 获取PHP项目的根目录路径
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Get Root Directory Path of a PHP project
提问by Nalaka526
I have this folder structure in my PHP project. (this is as shown in eclips)
我的 PHP 项目中有这个文件夹结构。（这如 eclips 所示）
-MySystem
+Code
+Data_Access
-Public_HTML
+css
+js
+Templates
-resources
When I try this code
当我尝试此代码时
echo $_SERVER['DOCUMENT_ROOT']
output is
输出是
D:/workspace
D:/工作区
How can I get the path to RootDirectory of the system (MySystem), without hardcoding the Folder Name?
如何在MySystem不硬编码文件夹名称的情况下获取系统 ( ) RootDirectory 的路径？
回答by Prasad Rajapaksha
For PHP >= 5.3.0try
对于PHP >= 5.3.0试试
PHP magic constants.
PHP魔法常量。
__DIR__
And make your path relative.
并使您的路径相对。
For PHP < 5.3.0try
对于PHP < 5.3.0尝试
dirname(__FILE__)
回答by Armin
When you say that
当你这么说
$_SERVER['DOCUMENT_ROOT']
contains this path:
包含此路径：
D:/workspace
Then D:is what you are looking for, isn't it?
In that case you could explode the string by slashes and return the first one:
那D:就是你要找的，不是吗？在这种情况下，您可以通过斜线分解字符串并返回第一个：
$pathInPieces = explode('/', $_SERVER['DOCUMENT_ROOT']);
echo $pathInPieces[0];
This will output the server's root directory.
这将输出服务器的根目录。
Update:When you use the constant DIRECTORY_SEPARATORinstead of the hardcoded slash ('/') this code is also working under Windows.
更新：当您使用常量DIRECTORY_SEPARATOR而不是硬编码的斜杠 ( '/') 时，此代码也适用于 Windows。
Update 2:The $_SERVERglobal variable is not always available. On command line (cli) for example. So you should use __DIR__instead of $_SERVER['DOCUMENT_ROOT']. __DIR__returns the path of the php file itself.
更新2：在$_SERVER全局变量并不总是可用的。例如在命令行（cli）上。所以你应该使用__DIR__而不是$_SERVER['DOCUMENT_ROOT']. __DIR__返回 php 文件本身的路径。
回答by dkinzer
回答by Hexodus
I want to point to the way Wordpress handles this:
我想指出 Wordpress 处理此问题的方式：
define( 'ABSPATH', dirname(dirname(__FILE__)) . '/' );
As Wordpress is very heavy used all over the web and also works fine locally I have much trust in this method.
由于 Wordpress 在整个网络上使用非常频繁，并且在本地也能正常工作，因此我非常信任这种方法。
回答by This_is_me
you can try:
$_SERVER['PATH_TRANSLATED']
你可以试试：
$_SERVER['PATH_TRANSLATED']
quote:
引用：
Filesystem- (not document root-) based path to the current script, after the server has done any virtual-to-real mapping. Note: As of PHP 4.3.2,
PATH_TRANSLATEDis no longer set implicitly under the Apache 2 SAPI in contrast to the situation in Apache 1, where it's set to the same value as theSCRIPT_FILENAMEserver variable when it's not populated by Apache.
This change was made to comply with the CGI specification that PATH_TRANSLATED should only exist ifPATH_INFOis defined. Apache 2 users may useAcceptPathInfo = Oninsidehttpd.confto definePATH_INFO
在服务器完成任何虚拟到真实映射之后，基于文件系统（不是文档根目录）的当前脚本的路径。注意：从 PHP 4.3.2 开始，
PATH_TRANSLATED与 Apache 1 中的情况相比，不再在 Apache 2 SAPI 下隐式设置，SCRIPT_FILENAME当它没有被 Apache 填充时，它被设置为与服务器变量相同的值。
进行此更改是为了符合 CGI 规范，即 PATH_TRANSLATED 仅在PATH_INFO定义时才存在。Apache 2 用户可以使用AcceptPathInfo = Oninsidehttpd.conf定义PATH_INFO
source: php.net/manual
来源： php.net/手册
回答by Waqar Alamgir
echo $pathInPieces = explode(DIRECTORY_SEPARATOR , __FILE__);
echo $pathInPieces[0].DIRECTORY_SEPARATOR;
回答by Mike Q
Summary
概括
This example assumes you always know where the apache root folder is '/var/www/' and you are trying to find the next folder path (e.g. '/var/www/my_website_folder'). Also this works from a script or the web browser which is why there is additional code.
此示例假设您始终知道 apache 根文件夹在哪里“/var/www/”，并且您正在尝试查找下一个文件夹路径（例如“/var/www/my_website_folder”）。这也适用于脚本或 Web 浏览器，这就是为什么有附加代码的原因。
Code PHP7
代码 PHP7
function getHtmlRootFolder(string $root = '/var/www/') {
// -- try to use DOCUMENT_ROOT first --
$ret = str_replace(' ', '', $_SERVER['DOCUMENT_ROOT']);
$ret = rtrim($ret, '/') . '/';
// -- if doesn't contain root path, find using this file's loc. path --
if (!preg_match("#".$root."#", $ret)) {
$root = rtrim($root, '/') . '/';
$root_arr = explode("/", $root);
$pwd_arr = explode("/", getcwd());
$ret = $root . $pwd_arr[count($root_arr) - 1];
}
return (preg_match("#".$root."#", $ret)) ? rtrim($ret, '/') . '/' : null;
}
Example
例子
echo getHtmlRootFolder();
Output:
输出：
/var/www/somedir/
Details:
细节：
Basically first tries to get DOCUMENT_ROOT if it contains '/var/www/' then use it, else get the current dir (which much exist inside the project) and gets the next path value based on count of the $root path. Note: added rtrim statements to ensure the path returns ending with a '/' in all cases . It doesn't check for it requiring to be larger than /var/www/ it can also return /var/www/ as a possible response.
基本上首先尝试获取 DOCUMENT_ROOT 如果它包含 '/var/www/' 然后使用它，否则获取当前目录（项目中存在很多）并根据 $root 路径的计数获取下一个路径值。注意：添加了 rtrim 语句以确保路径在所有情况下都返回以“/”结尾。它不会检查它是否需要大于 /var/www/ 它也可以返回 /var/www/ 作为可能的响应。
