使用 PHP 更新 XML 节点
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Updating XML node with PHP
提问by ptamzz
I've an XML file test.xml
我有一个 XML 文件 test.xml
<?xml version="1.0"?>
<info>
<user>
<name>
<firstname>FirstName</firstname>
<lastname>Last Name</lastname>
<nameCoordinate>
<xName>125</xName>
<yName>20</yName>
</nameCoordinate>
</name>
</user>
</info>
I'm trying to update the node xName & yName using PHP on a form submission. So, I've loaded the file using simplexml_load_file(). The PHP form action code is below
我正在尝试在表单提交中使用 PHP 更新节点 xName 和 yName。所以，我已经使用 simplexml_load_file() 加载了文件。PHP 表单操作代码如下
<?php
$xPostName = $_POST['xName'];
$yPostName = $_POST['yName'];
//load xml file to edit
$xml = simplexml_load_file('test.xml');
$xml->info->user->name->nameCoordinate->xName = $xPostName;
$xml->info->user->name->nameCoordinate->yName = $yPostName;
echo "done";
?>
I want to update the node values but the above code seems to be incorrect. Can anyone help me rectify it??
我想更新节点值，但上面的代码似乎不正确。谁能帮我改正？？
UPDATE: My question is somewhat similar to this Updating a XML file using PHPbut here, I'm loading the XML from an external file and also I'm updating an element, not an attribute. That's where my confusion lies.
更新：我的问题有点类似于使用 PHP 更新 XML 文件，但在这里，我从外部文件加载 XML，并且我正在更新元素，而不是属性。这就是我的困惑所在。
回答by Josh Davis
You're not accessing the right node. In your example, $xmlholds the root node <info/>. Here's a great tip: always name the variable that holds your XML document after its root node, it will prevent such confusion.
您没有访问正确的节点。在您的示例中，$xml保存根节点<info/>。这里有一个很好的提示：始终在根节点之后命名保存 XML 文档的变量，这样可以防止这种混淆。
Also, as Ward Muylaert pointed out, you need to save the file.
此外，正如 Ward Muylaert 指出的，您需要保存文件。
Here's the corrected example:
这是更正的示例：
// load the document
// the root node is <info/> so we load it into $info
$info = simplexml_load_file('test.xml');
// update
$info->user->name->nameCoordinate->xName = $xPostName;
$info->user->name->nameCoordinate->yName = $yPostName;
// save the updated document
$info->asXML('test.xml');
回答by Ward Muylaert
回答by Ruhith Udakara
try like this.
像这样尝试。
$xmlDoc = new \DOMDocument;
$xmlDoc->load('Books.xml');
$response = $xmlDoc->getElementsByTagName('Text');
foreach ($response as $node){
$node->nodeValue = 'test';
}
$xmlDoc->saveXML();
this might not the best answer but it worked for me.
这可能不是最好的答案，但它对我有用。
