Python 如何删除字符串中某个字符后的所有内容？
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How to delete everything after a certain character in a string?
提问by ThatGuyJay
How would I delete everything after a certain character of a string in python? For example I have a string containing a file path and some extra characters. How would I delete everything after .zip? I've tried rsplitand split, but neither included the .zip when deleting extra characters.
如何在python中某个字符串的某个字符后删除所有内容？例如，我有一个包含文件路径和一些额外字符的字符串。我如何删除 .zip 之后的所有内容？我试过rsplitand split，但在删除额外字符时都没有包含 .zip 。
Any suggestions?
有什么建议？
采纳答案by Andrew Clark
Just take the first portion of the split, and add '.zip'back:
只需取出拆分的第一部分，然后添加'.zip'回来：
s = 'test.zip.zyz'
s = s.split('.zip', 1)[0] + '.zip'
Alternatively you could use slicing, here is a solution where you don't need to add '.zip'back to the result (the 4comes from len('.zip')):
或者，您可以使用切片，这是一个不需要添加'.zip'回结果的解决方案（4来自len('.zip')）：
s = s[:s.index('.zip')+4]
Or another alternative with regular expressions:
或者使用正则表达式的另一种选择：
import re
s = re.match(r'^.*?\.zip', s).group(0)
回答by óscar López
Use slices:
使用切片：
s = 'test.zip.xyz'
s[:s.index('.zip') + len('.zip')]
=> 'test.zip'
And it's easy to pack the above in a little helper function:
并且很容易将上面的内容打包到一个小辅助函数中：
def removeAfter(string, suffix):
return string[:string.index(suffix) + len(suffix)]
removeAfter('test.zip.xyz', '.zip')
=> 'test.zip'
回答by jh314
You can use the remodule:
您可以使用该re模块：
import re
re.sub('\.zip.*','.zip','test.zip.blah')
回答by Rob?
str.partition:
str.partition：
>>> s='abc.zip.blech'
>>> ''.join(s.partition('.zip')[0:2])
'abc.zip'
>>> s='abc.zip'
>>> ''.join(s.partition('.zip')[0:2])
'abc.zip'
>>> s='abc.py'
>>> ''.join(s.partition('.zip')[0:2])
'abc.py'
回答by joente
I think it's easy to create a simple lambda function for this.
我认为为此创建一个简单的 lambda 函数很容易。
mystrip = lambda s, ss: s[:s.index(ss) + len(ss)]
Can be used like this:
可以这样使用：
mystr = "this should stay.zipand this should be removed."
mystrip(mystr, ".zip") # 'this should stay.zip'
