在 bash if 语句中使用通配符
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Using wildcards in bash if statement
提问by Rami Chaouki
I wrote the following code in the bash shell. It's supposed to take the positional parameter, and if it starts with a dash "-", it's supposed to input an error message.
我在 bash shell 中编写了以下代码。它应该采用位置参数，如果它以破折号“-”开头，则应该输入错误消息。
But for some reason, the if statement always gets skipped. It only functions if I literally input -*
但出于某种原因，if 语句总是被跳过。只有当我从字面上输入 -* 时它才起作用
I get the impression that the fix has something to do with the "$".
我的印象是修复与“$”有关。
Here is a snippet of the code:
这是代码的一个片段：
EXECNAME=
if [ "$EXECNAME" = "-*" ]; then
echo "error: invalid executable name"
fi
回答by anubhava
You can use double square brackets [[and ]]without use of quotes on matching pattern for glob support in BASH:
您可以使用双括号[[，并]]没有使用上的BASH水珠支持匹配模式的报价：
[[ "$EXECNAME" = -* ]] && echo "error: invalid executable name"
回答by holygeek
For matching against glob pattern I prefer to use case:
为了匹配 glob 模式，我更喜欢使用case：
case $EXECNAME in
-*) echo "error: invalid executable name"
esac
