Bash 正则表达式匹配不起作用
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Bash regex matching not working
提问by pillarOfLight
so I have this function
所以我有这个功能
function test(){
local output="CMD[hahahhaa]"
if [[ "$output" =~ "/CMD\[.*?\]/" ]]; then
echo "LOOL"
else
echo "$output"
fi;
}
however executing test in command line would output $output instead of "LOOL" despite the fact that the pattern should be matching $output...
然而，尽管模式应该与 $output 匹配，但在命令行中执行测试将输出 $output 而不是“LOOL”...
what did I do wrong?
我做错了什么？
回答by Ravi Thapliyal
Don't use quotes ""
不要使用引号 ""
if [[ "$output" =~ ^CMD\[.*?\]$ ]]; then
Update :更新 ：(in response to @frhd)（回应@frhd）
Well, the regex operator =~expects an unquotedregular expression on its RHS and does only a sub-string match unless the anchors ^(start of input) and $(end of input) are also used to make it match the whole of the LHS.
好吧，正则表达式运算符=~期望在其 RHS 上有一个不带引号的正则表达式，并且只进行子字符串匹配，除非还使用锚点^（输入开始）和$（输入结束）使其与整个 LHS 匹配。
Quotations""override this behaviour and force a simple string match instead i.e. the matcher starts looking for all these characters \[.*?\]literally.
引用""会覆盖此行为并强制进行简单的字符串匹配，即匹配器开始\[.*?\]逐字查找所有这些字符。
