在 bash 中循环时更改数组值
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change array value while looping in bash
提问by VextoR
The code
编码
SourceFolder[0]=""
SourceFolder[1]="inbound2"
SourceFolder[2]="inbound3"
for i in "${!SourceFolder[@]}"
do
if [ -z "${SourceFolder[$i]}"]; then
${SourceFolder[$i]} = "TEST"
fi
done
${SourceFolder[$i]} = "TEST"- doesn't work
${SourceFolder[$i]} = "TEST"- 不起作用
it says
它说
=: command not found
=：找不到命令
How to change value in current loop index in an array?
如何更改数组中当前循环索引的值？
回答by UmNyobe
Because of the first space =is not interpreted as an assignment. There is a full explanation on So.
Btw ${SourceFolder[$i]}evaluate the array element, which is not what you want to do. For instance for the first one it is the empty string.
顺便说一句，${SourceFolder[$i]}评估数组元素，这不是您想要做的。例如，第一个它是空字符串。
Replaces with SourceFolder[$i]=
替换为 SourceFolder[$i]=
回答by xck
You must change indexnumber in the your array:
您必须更改数组中的索引号：
ARRAYNAME[indexnumber]=value
ok, you have array is:
好的，你的数组是：
array=(one two three)
you can add count to your script for initialize and change element for array indexnumber, example:
您可以在脚本中添加计数以初始化和更改数组索引号的元素，例如：
#!/bin/bash
count=0
array=(one two three)
for i in ${array[@]}
do
echo "$i"
array[$count]="$i-indexnumber-is-$count"
count=$((count + 1))
echo $count
done
echo ${array[*]}
Result:
结果：
bash test-arr.sh
one
1
two
2
three
3
one-indexnumber-is-0 two-indexnumber-is-1 three-indexnumber-is-2
