java 使用 Apache Camel 发送 POST 请求
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Send POST Request using Apache Camel
提问by user6641655
I was able to send a GET request using Apache Camel to a REST service and now I'm trying to send a POST request with a JSON body using Apache Camel. I wasn't able to figure out how to add the JSON body and send the request. How can I add a JSON body, send the request and get the response code?
我能够使用 Apache Camel 向 REST 服务发送 GET 请求，现在我正在尝试使用 Apache Camel 发送带有 JSON 正文的 POST 请求。我无法弄清楚如何添加 JSON 正文并发送请求。如何添加 JSON 正文、发送请求并获取响应代码？
回答by kris_k
Below you can find a sample Route which sends (every 2 seconds) the json, using POST method to the server, in the example it is localhost:8080/greeting. There is also a way to get the response presented:
您可以在下面找到一个示例路由，它使用 POST 方法向服务器发送（每 2 秒）json，在示例中它是 localhost:8080/greeting。还有一种方法可以获得响应：
from("timer://test?period=2000")
.process(exchange -> exchange.getIn().setBody("{\"title\": \"The title\", \"content\": \"The content\"}"))
.setHeader(Exchange.HTTP_METHOD, constant("POST"))
.setHeader(Exchange.CONTENT_TYPE, constant("application/json"))
.to("http://localhost:8080/greeting")
.process(exchange -> log.info("The response code is: {}", exchange.getIn().getHeader(Exchange.HTTP_RESPONSE_CODE)));
Usually it is not a good idea to prepare json manually. You can use e.g.
通常手动准备json不是一个好主意。你可以使用例如
<dependency>
<groupId>org.apache.camel</groupId>
<artifactId>camel-gson</artifactId>
</dependency>
to perform marshalling for you. Assuming you have a Greeting class defined you can modify the Route by removing the first processor and using the following code instead:
为您执行编组。假设您定义了 Greeting 类，您可以通过删除第一个处理器并使用以下代码来修改路由：
.process(exchange -> exchange.getIn().setBody(new Greeting("The title2", "The content2")))
.marshal().json(JsonLibrary.Gson)
Further reading: http://camel.apache.org/http.htmlIt is worth noting that there is also http4 component (they use different version of Apache HttpClient under the hood).
进一步阅读：http: //camel.apache.org/http.html 值得注意的是还有 http4 组件（它们在引擎盖下使用不同版本的 Apache HttpClient）。
回答by user12766534
//This code is for sending post request and getting response
public static void main(String[] args) throws Exception {
CamelContext c=new DefaultCamelContext();
c.addRoutes(new RouteBuilder() {
@Override
public void configure() throws Exception {
from("direct:start")
.process(new Processor() {
public void process(Exchange exchange) throws Exception {
System.out.println("i am worlds fastest flagship processor ");
exchange.getIn().setHeader("CamelHttpMethod", "POST");
exchange.getIn().setHeader("Content-Type", "application/json");
exchange.getIn().setHeader("accept", "application/json");
}
})
// to the http uri
.to("https://www.google.com")
// to the consumer
.to("seda:end");
}
});
c.start();
ProducerTemplate pt = c.createProducerTemplate();
// for sending request
pt.sendBody("direct:start","{\"userID\": \"678\",\"password\": \"password\",
\"ID\": \"123\" }");
ConsumerTemplate ct = c.createConsumerTemplate();
String m = ct.receiveBody("seda:end",String.class);
System.out.println(m);
}
回答by Saurabh Nayar
This is how you can do it:
你可以这样做：
from("direct:start")
.setHeader(Exchange.HTTP_METHOD, constant("POST"))
.to("http://www.google.com");
Current Camel Exchange's body will get POSTED to the URL end point.
当前 Camel Exchange 的正文将被发布到 URL 端点。
