来自 bash 脚本的电子邮件
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email from bash script
提问by Jim
#!/bin/bash
MESSAGE="Line one. /n"
MESSAGE="$MESSAGE Line two. /n"
MESSAGE="$MESSAGE Line three."
echo $MESSAGE | mail -s "test" "[email protected]"
Is that how I should get each line, on its own line?
这是我应该如何在自己的行上获取每行？
回答by Matthew Flaschen
Use a heredoc.
使用heredoc。
mail -s "test" "[email protected]" << END_MAIL
Line one.
Line two.
Line three.
END_MAIL
回答by Jim
Change:
改变：
echo $MESSAGE | mail -s "test" "[email protected]"
To:
到：
echo -e $MESSAGE | mail -s "test" "[email protected]"
回答by DigitalRoss
The heredoc advice is good, plus you might want to consider using mailxfor which there exists a Posix standard or perhaps sendmailwhich will exist if the mailer is either sendmail or postfix. (I'm not sure about qmail.)
Heredoc 建议很好，另外您可能要考虑使用mailx存在 Posix 标准的地方，或者sendmail如果邮件程序是 sendmail 或 postfix可能会存在。（我不确定 qmail。）
Unless using sendmail, it's also a good idea to set the MAILRCvariable to /dev/nullto bypass the user's configuration script, if any.
除非使用 sendmail，否则最好将该MAILRC变量设置/dev/null为绕过用户的配置脚本（如果有）。
