在 Python 中从 curl 读取 JSON 文件
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Reading JSON files from curl in Python
提问by Malluce
Let's say I have a command in Python that looks like
假设我在 Python 中有一个命令，看起来像
command = 'curl ...etc" > result.json'
subprocess.call(command, shell = True)
file = open("result.json").read()
What it does right now is GET from the place I curl and store the result in result.json, then I open it to read it. I wonder if there's way I can read it directly without storing to local first?
它现在所做的是从我卷曲的地方 GET 并将结果存储在 result.json 中，然后我打开它来阅读它。我想知道是否有办法直接读取它而无需先存储到本地？
采纳答案by Esparta Palma
You can use the stdlib (json& urllib2) to avoid the use of external commands:
您可以使用 stdlib ( json& urllib2) 来避免使用外部命令：
import json
import urllib2
url = "http://httpbin.org/get"
response = urllib2.urlopen(url)
data = response.read()
values = json.loads(data)
But I'd recommend to use requeststo simplify your code. Here a sample from the docs:
但我建议使用请求来简化您的代码。这是文档中的示例：
import requests
r = requests.get('https://api.github.com/user', auth=('user', 'pass'))
r.status_code
200
r.headers['content-type']
'application/json; charset=utf8'
r.encoding
'utf-8'
r.text
u'{"type":"User"...'
r.json()
{u'private_gists': 419, u'total_private_repos': 77, ...}
Python 3 Update
Python 3 更新
Please consider that in Python3 urllib2 does not exists anymore, you should use urllibwhich comes in the standard library
请考虑在 Python3 中 urllib2 不再存在，您应该使用标准库中的urllib
req = urllib.request.Request(url)
response = urllib.request.urlopen(req)
data = response.read()
values = json.loads(data)
回答by jfs
In general, if you have a command that prints to its stdout then you could get the output without storing it on the disk using subprocess.check_output:
通常，如果您有一个打印到其标准输出的命令，那么您可以使用以下命令获取输出而无需将其存储在磁盘上subprocess.check_output：
from subprocess import check_output
output = check_output(['source', 'arg1', 'arg2'])
In your case, you could use urllib2or requestsPython modules instead of curlcommand as shown in @Esparta Palma's answer.
在您的情况下，您可以使用urllib2或requestsPython 模块而不是@Esparta Palma's answer 中curl所示的命令。
