Python，计数器原子增量
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Python, counter atomic increment
提问by user2983041
How can I translate the following code from Java to Python?
如何将以下代码从 Java 转换为 Python？
AtomicInteger cont = new AtomicInteger(0);
int value = cont.getAndIncrement();
采纳答案by viraptor
Most likely with an threading.Lockaround any usage of that value. There's no atomic modification in Python unless you use pypy (if you do, have a look at __pypy__.thread.atomicin stm version).
最有可能threading.Lock使用该值的任何用法。除非您使用 pypy（如果使用，请查看__pypy__.thread.atomicstm 版本），否则 Python 中没有原子修改。
回答by Will Manley
itertools.countreturns an iterator which will perform the equivalent to getAndIncrement()on each iteration.
itertools.count返回一个迭代器，它将getAndIncrement()在每次迭代中执行等价于。
Example:
例子：
import itertools
cont = itertools.count()
value = next(cont)
回答by user48956
This will perform the same function, although its not lockless as the name 'AtomicInteger' would imply.
这将执行相同的功能，尽管它不像名称“AtomicInteger”所暗示的那样是无锁的。
Note other methods are also not strictly lockless -- they rely on the GIL and are not portable between python interpreters.
请注意，其他方法也不是严格无锁的——它们依赖于 GIL，并且在 python 解释器之间不可移植。
class AtomicInteger():
def __init__(self, value=0):
self._value = value
self._lock = threading.Lock()
def inc(self):
with self._lock:
self._value += 1
return self._value
def dec(self):
with self._lock:
self._value -= 1
return self._value
@property
def value(self):
with self._lock:
return self._value
@value.setter
def value(self, v):
with self._lock:
self._value = v
return self._value
