Python 类型错误：“范围”对象不支持项目分配
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TypeError: 'range' object does not support item assignment
提问by user2840982
I was looking at some python 2.xcode and attempted to translate it to py 3.xbut I'm stuck on this section. Could anyone clarify what is wrong?
我正在查看一些python 2.x代码并试图将其翻译为，py 3.x但我被困在这一部分。任何人都可以澄清什么是错的？
import random
emails = {
"x": "[REDACTED]@hotmail.com",
"x2": "[REDACTED]@hotmail.com",
"x3": "[REDACTED]@hotmail.com"
}
people = emails.keys()
#generate a number for everyone
allocations = range(len(people))
random.shuffle(allocations)
This was the error given:
这是给出的错误：
TypeError: 'range' object does not support item assignment
采纳答案by Tim
In Python 3, rangereturns a lazy sequence object - it does not return a list. There is no way to rearrange elements in a range object, so it cannot be shuffled.
在 Python 3 中，range返回一个惰性序列对象——它不返回一个列表。无法重新排列 range 对象中的元素，因此无法对其进行洗牌。
Convert it to a list before shuffling.
在洗牌之前将其转换为列表。
allocations = list(range(len(people)))
