通过 sftp 从远程服务器下载 PHP
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PHP download from remote server via sftp
提问by user2589167
This may have been asked before, I'm new to PHP and I'm trying to learn as much as I can, but this has really thrown me.
之前可能有人问过这个问题，我是 PHP 的新手，我正在努力学习尽可能多的知识，但这确实让我感到困惑。
Basically what I want to know is, how would I use PHP code to get it to download everything from a remote server to a local location. It's getting it to download everything not just one file that I'm stuck on. So please can someone show/explain to me how I would do this?
基本上我想知道的是，我将如何使用 PHP 代码让它将所有内容从远程服务器下载到本地位置。它可以下载所有内容，而不仅仅是我卡住的一个文件。所以请有人向我展示/解释我将如何做到这一点？
What I've got so far:
到目前为止我所得到的：
<?php
$connection - ssh2_connect('example.com', 22);
ssh2_auth_password($connection, 'username', 'password');
$remote_dir="/remote_dir/";
$local_dir="/local_dir/";
$remote ="$remote_dir";
$stream = ssh2_exec($connection, $remote);
stream_set_blocking($stream,true);
$command=fread($stream,4096);
$array=explode(\n,$command);
$total_files=sizeof($array);
for($i=0;$i<$total_files;$i+++){
$file_name=trim($array[$i]);
if($file_name!=''{
$remote_file=$remote_dir.$file_name;
$local_file=$local_dir.$file_name;
if(ssh2_scp_recv($connection, $remote_file,$local_file)){
echo "File ".$file_name." was copied to $local_dir<br />";
}
}
}
fclose($stream);
?>
I think my $remote ="$remote_dir"; is wrong, and to be honest I've got $filename when I want the whole directory, this is all I have so far.
我想我的 $remote ="$remote_dir"; 是错误的，老实说，当我想要整个目录时，我已经有了 $filename，这就是我目前所拥有的。
回答by Prix
Here is a small code on how to read the folder and download all its files:
这是一个关于如何读取文件夹并下载其所有文件的小代码：
<?php
$host = 'localhost';
$port = 22;
$username = 'username';
$password = 'password';
$remoteDir = '/must/be/the/complete/folder/path';
$localDir = '/can/be/the/relative/or/absolute/local/path';
if (!function_exists("ssh2_connect"))
die('Function ssh2_connect not found, you cannot use ssh2 here');
if (!$connection = ssh2_connect($host, $port))
die('Unable to connect');
if (!ssh2_auth_password($connection, $username, $password))
die('Unable to authenticate.');
if (!$stream = ssh2_sftp($connection))
die('Unable to create a stream.');
if (!$dir = opendir("ssh2.sftp://{$stream}{$remoteDir}"))
die('Could not open the directory');
$files = array();
while (false !== ($file = readdir($dir)))
{
if ($file == "." || $file == "..")
continue;
$files[] = $file;
}
foreach ($files as $file)
{
echo "Copying file: $file\n";
if (!$remote = @fopen("ssh2.sftp://{$stream}/{$remoteDir}{$file}", 'r'))
{
echo "Unable to open remote file: $file\n";
continue;
}
if (!$local = @fopen($localDir . $file, 'w'))
{
echo "Unable to create local file: $file\n";
continue;
}
$read = 0;
$filesize = filesize("ssh2.sftp://{$stream}/{$remoteDir}{$file}");
while ($read < $filesize && ($buffer = fread($remote, $filesize - $read)))
{
$read += strlen($buffer);
if (fwrite($local, $buffer) === FALSE)
{
echo "Unable to write to local file: $file\n";
break;
}
}
fclose($local);
fclose($remote);
}
You can also resume this code to (it will not copy directories):
您还可以将此代码恢复到（它不会复制目录）：
while (false !== ($file = readdir($dirHandle)))
{
if ($file == "." || $file == "..")
continue;
echo "Copying file: $file\n";
if(!ssh2_scp_recv($connection, $remoteDir . $file, $localDir . $file))
echo "Could not download: ", $remoteDir, $file, "\n";
}
If you do not use the full path on the remote folder it will not work:
如果您不使用远程文件夹上的完整路径，它将不起作用：
opendir("ssh2.sftp://{$stream}{$remoteDir}")
回答by Arth Du
Update: I was kindly corrected that this doesn't use sftp, but instead uses ftps. Here's a Stackoverflow link discussing using PHP to do SFTP.
更新：我被亲切地纠正，这不使用 sftp，而是使用 ftps。这是讨论使用 PHP 执行 SFTP的 Stackoverflow 链接。
The PHP docsalready cover most of what you should need for this. Here's an example for fetching a list of the contents in the remote directory:
在PHP文档已经覆盖了大部分的，如果您需要什么这一点。这是获取远程目录中内容列表的示例：
<?php
// set up basic connection
$ftp_server = "example.com";
$conn_id = ftp_ssl_connect($ftp_server);
// login with username and password
$ftp_user_name = "myuser";
$ftp_user_pass = "mypass";
$login_result = ftp_login($conn_id, $ftp_user_name, $ftp_user_pass);
ftp_pasv($conn_id, true);
// check connection
if ((!$conn_id) || (!$login_result)) {
echo "FTP connection has failed!";
echo "Attempted to connect to $ftp_server for user $ftp_user_name";
exit;
} else {
echo "Connected to $ftp_server, for user $ftp_user_name";
}
$buff = ftp_rawlist($conn_id, '.');
var_dump($buff);
ftp_close($conn_id);
?>
