bash 阅读：shell 脚本中的非法选项 -s
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read: Illegal option -s in shell scripting
提问by Vicky
I tried running this code:
我尝试运行此代码：
#!/bin/bash
read -s "Password: " password
With command:
使用命令：
run sh init.sh
it throws an error: read: Illegal option -s. Any help.
它抛出一个错误：read: Illegal option -s。任何帮助。
回答by Geoff Nixon
I take it you're using Debian/Ubuntu, or a BSD-derivative?
我认为您使用的是 Debian/Ubuntu 或 BSD 衍生版本？
When you execute a command like run sh init.sh(although I'm not myself familiar with this runcommand) you are overriding the #!/bin/bashshebang. In your case shis a strictly compliant POSIX shell like dash, where, in fact, the only argument to readthat is not an extension is -r.
当您执行类似run sh init.sh（虽然我自己不熟悉此run命令）之类的命令时，您正在覆盖#!/bin/bashshebang。在您的情况下sh是一个严格兼容的 POSIX shell，例如dash，其中，实际上，唯一read不是扩展名的参数是-r.
So maybe you'd want to use run bash init.shinstead?
所以也许你想run bash init.sh改用？
回答by anubhava
You need to use -poption for prompt:
您需要使用-p选项prompt：
read -sp "Password: " password
As per help read:
根据help read：
-p prompt output the string PROMPT without a trailing newline before
attempting to read
