C# 读取一个 xslx 文件并转换为 List

read an xslx file and convert to List

提问by Ozkan

I have a xslx file with following data

我有一个包含以下数据的 xslx 文件

    www.url.com
    www.url.com
    www.url.com
    www.url.com
    www.url.com
    www.url.com
    www.url.com
    www.url.com
    ...

Like you can see I have only 1 column used and a lot of rows. I need to read that column from the xslx file somehow and convert it to List<string>.

就像您看到的那样，我只使用了 1 列和很多行。我需要以某种方式从 xslx 文件中读取该列并将其转换为List<string>.

Any help?

有什么帮助吗？

Thanks!

谢谢！

采纳答案by Antonio Bakula

You can use EPPlus, it's simple, something like this :

您可以使用EPPlus，这很简单，如下所示：

  var ep = new ExcelPackage(new FileInfo(excelFile));
  var ws = ep.Workbook.Worksheets["Sheet1"];

  var domains = new List<string>();
  for (int rw = 1; rw <= ws.Dimension.End.Row; rw++)
  {
    if (ws.Cells[rw, 1].Value != null)
     domains.Add(ws.Cells[rw, 1].Value.ToString());
  }

回答by Matteo Migliore

You can use OOXML to read the file and this library simplify your work http://simpleooxml.codeplex.com.

您可以使用 OOXML 来读取文件，这个库简化了您的工作http://simpleooxml.codeplex.com。

回答by Mike Corcoran

the easiest way is to use OleDb, you can do something like this:

最简单的方法是使用 OleDb，你可以这样做：

List<string> values = new List<string>();

string constr = "Provider=Microsoft.ACE.OLEDB.12.0;Data Source=C:\your\path\file.xlsx;Extended Properties=\"Excel 12.0 Xml;HDR=NO;\"";
using (OleDbConnection conn = new OleDbConnection(constr))
{
    conn.Open();
    OleDbCommand command = new OleDbCommand("Select * from [SheetName$]", conn);
    OleDbDataReader reader = command.ExecuteReader();
    if (reader.HasRows)
    {
        while (reader.Read())
        {
            // this assumes just one column, and the value is text
            string value = reader[0].ToString();
            values.Add(value);
        }
    }
}

foreach (string value in values)
    Console.WriteLine(value);