Java 将十六进制字符串转换为 BigInt
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Java convert a HEX String to a BigInt
提问by user524156
Hi am trying to convert a hex string such as String hexStr = "1b0ee1e3"; to a bigInt, ideally i'd like to convert hexStr to a bigint in its decimal form,
嗨，我正在尝试转换十六进制字符串，例如 String hexStr = "1b0ee1e3"; 到 bigInt，理想情况下，我想将 hexStr 转换为十进制形式的 bigint，
I can convert a string to a bigInt w/o issues but when the string contains hex values i run into problems
我可以将字符串转换为没有问题的 bigInt，但是当字符串包含十六进制值时，我遇到了问题
采纳答案by Jon Skeet
Have you tried:
你有没有尝试过：
BigInteger bigInt = new BigInteger(hexString, 16);
For example:
例如：
import java.math.*;
public class Test {
public static void main(String[] args) {
String hexStr = "1b0ee1e3";
BigInteger bigInt = new BigInteger(hexStr, 16);
System.out.println(bigInt); // Prints 453960163
}
}
