Python 映射到列表错误:系列对象不可调用
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Map to List error: Series object not callable
提问by Quantum Dreamer
from nsepy import get_history
from datetime import date
import datetime
import pandas as pd
import numpy as np
file = r'C:\Users\Raspberry-Pi\Desktop\Desktop\List.xlsx'
list = pd.read_excel(file)
list = list['SYMBOL']
start = date.today()-datetime.timedelta(days = 10)
end = date.today()
symb = get_history(symbol='INFY',start = start,end = end)
h = symb.tail(3).High.tolist()
l = symb.tail(3).Low.tolist()
print(type(h))
print(type(l))
x = map(lambda a,b:a-b,h,l)
print(type(x))
x = list(x)
I am getting error:
我收到错误:
series object not callable
系列对象不可调用
and its pointing to x = list(x)
line.
并且它指向x = list(x)
线。
采纳答案by jezrael
But I think you can omit map
and use simple subtract and then convert to list
:
但我认为您可以省略map
并使用简单的减法,然后转换为list
:
symb = get_history(symbol='INFY',start = start,end = end)
print ((symb.tail(3).High - symb.tail(3).Low).tolist())
Also don't use variable list
(reserved word in python) rather L
(or something else):
也不要使用变量list
(python 中的保留字)而不是 L
(或其他东西):
L = pd.read_excel(file)
L = L['SYMBOL']
Sample:
样本:
import pandas as pd
symb = pd.DataFrame({'High':[8,9,7,5,3,4],'Low':[1,2,3,1,0,1]})
print (symb)
High Low
0 8 1
1 9 2
2 7 3
3 5 1
4 3 0
5 4 1
print ((symb.tail(3).High - symb.tail(3).Low).tolist())
[4, 3, 3]
EDIT:
编辑:
I try simulate problem:
我尝试模拟问题:
list = pd.DataFrame({'SYMBOL':['sss old','dd','old']})
print (list)
SYMBOL
0 sss old
1 dd
2 old
list = list['SYMBOL']
print (list)
0 sss old
1 dd
2 old
Name: SYMBOL, dtype: object
print (type(list))
<class 'pandas.core.series.Series'>
x = [1,2,3]
#list is Series, not function
x = list(x)
print (x)
TypeError: 'Series' object is not callable
If change list
to L
, is important reopen python console, because still same error.
如果更改list
为L
, 很重要重新打开 python 控制台,因为仍然出现相同的错误。
So this works perfectly:
所以这完美地工作:
df = pd.DataFrame({'SYMBOL':['sss old','dd','old']})
print (df)
SYMBOL
0 sss old
1 dd
2 old
L = df['SYMBOL']
print (L)
0 sss old
1 dd
2 old
Name: SYMBOL, dtype: object
x = [1,2,3]
x = list(x)
print (x)
[1, 2, 3]
回答by hpaulj
list(x)
normally means turn x
into a list
object. It's a function that creates a list object. But near the top you redefined list
:
list(x)
通常意味着x
变成一个list
物体。它是一个创建列表对象的函数。但在你重新定义的顶部附近list
:
list = pd.read_excel(file)
Now list
is now a pandas series
object (as the error message says), and it does not function as a function, i.e. it is not callable
, it cannot be used with ()
.
Now 现在list
是一个 pandasseries
对象(如错误消息所述),并且它不作为函数运行,即它不是callable
,它不能与()
.
Use a different name for this object. Use a silly name like foo
if you can't think of a better descriptor.
为此对象使用不同的名称。foo
如果您想不出更好的描述符,请使用愚蠢的名称。
回答by saikumarm
The problem is that you have reassigned reserve word
问题是你重新分配了保留字
list = pd.read_excel(file)
list = list['SYMBOL']
hence list here is just a list of ['S', 'Y', 'M', 'B'..]
. Use another name for this definition the program will work fine
因此这里的列表只是一个列表['S', 'Y', 'M', 'B'..]
。为这个定义使用另一个名称程序将正常工作