Python Django：显示选择值
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Django: Display Choice Value
提问by Shankze
models.py:
模型.py：
class Person(models.Model):
name = models.CharField(max_length=200)
CATEGORY_CHOICES = (
('M', 'Male'),
('F', 'Female'),
)
gender = models.CharField(max_length=200, choices=CATEGORY_CHOICES)
to_be_listed = models.BooleanField(default=True)
description = models.CharField(max_length=20000, blank=True)
views.py:
视图.py：
def index(request):
latest_person_list2 = Person.objects.filter(to_be_listed=True)
return object_list(request, template_name='polls/schol.html',
queryset=latest_person_list, paginate_by=5)
On the template, when I call person.gender, I get 'M'or 'F'instead of 'Male'or 'Female'.
在模板上，当我调用 时person.gender，我得到'M'or'F'代替'Male'or 'Female'。
How to display the value ('Male'or 'Female') instead of the code ('M'/'F')?
如何显示值（'Male'或'Female'）而不是代码（'M'/ 'F'）？
回答by jMyles
It looks like you were on the right track - get_FOO_display()is most certainly what you want:
看起来您走在正确的轨道上 -get_FOO_display()这肯定是您想要的：
In templates, you don't include ()in the name of a method. Do the following:
在templates 中，您不包括()在方法的名称中。请执行下列操作：
{{ person.get_gender_display }}
回答by Muhammad Faizan Fareed
For every field that has choices set, the object will have a get_FOO_display() method, where FOO is the name of the field. This method returns the “human-readable” value of the field.
对于每个设置了选项的字段，对象都有一个 get_FOO_display() 方法，其中 FOO 是字段的名称。此方法返回字段的“人类可读”值。
In Views
在视图中
person = Person.objects.filter(to_be_listed=True)
context['gender'] = person.get_gender_display()
In Template
在模板中
{{ person.get_gender_display }}
回答by Daniel O'Brien
Others have pointed out that a get_FOO_display method is what you need. I'm using this:
其他人指出 get_FOO_display 方法正是您所需要的。我正在使用这个：
def get_type(self):
return [i[1] for i in Item._meta.get_field('type').choices if i[0] == self.type][0]
which iterates over all of the choices that a particular item has until it finds the one that matches the items type
它迭代特定项目的所有选择，直到找到与项目类型匹配的选择
