Python 如何将十六进制三元组转换为 RGB 元组并返回？
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How do I convert a hex triplet to an RGB tuple and back?
提问by rectangletangle
I'd like to convert a hex triplet to an RGB tuple and then convert a tuple to a hex triplet.
我想将十六进制三元组转换为 RGB 元组，然后将元组转换为十六进制三元组。
采纳答案by martineau
You can use a look-up table with some slicing and shifts — all relatively fast operations — to create a couple of functions that will work unchanged in both Python 2 and 3:
您可以使用带有一些切片和移位（所有相对较快的操作）的查找表来创建几个函数，这些函数在 Python 2 和 3 中都可以保持不变：
_NUMERALS = '0123456789abcdefABCDEF'
_HEXDEC = {v: int(v, 16) for v in (x+y for x in _NUMERALS for y in _NUMERALS)}
LOWERCASE, UPPERCASE = 'x', 'X'
def rgb(triplet):
return _HEXDEC[triplet[0:2]], _HEXDEC[triplet[2:4]], _HEXDEC[triplet[4:6]]
def triplet(rgb, lettercase=LOWERCASE):
return format(rgb[0]<<16 | rgb[1]<<8 | rgb[2], '06'+lettercase)
if __name__ == '__main__':
print('{}, {}'.format(rgb('aabbcc'), rgb('AABBCC')))
# -> (170, 187, 204), (170, 187, 204)
print('{}, {}'.format(triplet((170, 187, 204)),
triplet((170, 187, 204), UPPERCASE)))
# -> aabbcc, AABBCC
print('{}, {}'.format(rgb('aa0200'), rgb('AA0200')))
# -> (170, 2, 0), (170, 2, 0)
print('{}, {}'.format(triplet((170, 2, 0)),
triplet((170, 2, 0), UPPERCASE)))
# -> aa0200, AA0200
回答by dan_waterworth
def hex_to_int_color(v):
if v[0] == '#':
v = v[1:]
assert(len(v) == 6)
return int(v[:2], 16), int(v[2:4], 16), int(v[4:6], 16)
def int_to_hex_color(v):
assert(len(v) == 3)
return '#%02x%02x%02x' % v
回答by adamk
>>> import struct
>>> rgbstr='aabbcc'
>>> struct.unpack('BBB',rgbstr.decode('hex'))
(170, 187, 204)
and
和
>>> rgb = (50,100,150)
>>> struct.pack('BBB',*rgb).encode('hex')
'326496'
回答by pyfunc
A very simplistic approach to convert rgb to hex
将 rgb 转换为十六进制的一种非常简单的方法
>>> rgb = (255, 255, 255)
>>> r, g , b = rgb
>>> hex(r)
'0xff'
>>> hex(r) + hex(g)[2:] + hex(b)[2:]
'0xffffff'
>>>
A simplistic approach to convert Hex to rgb
将十六进制转换为 rgb 的简单方法
>>> h = '0xffffff'
>>> h1, h2, h3 = h[0:4], '0x' + h[4:6], '0x' + h[6:8]
>>> h1, h2, h3
('0xff', '0xff', '0xff')
>>> r, g , b = int(h1, 16), int(h2, 16), int(h3, 16)
>>> r, g, b
(255, 255, 255)
Use a module which provides some these facility: webcolors
使用提供以下功能的模块：webcolors
>>> hex_to_rgb('#000080')
(0, 0, 128)
>>> rgb_to_hex((255, 255, 255))
'#ffffff'
Function doc:
功能文档：
hex_to_rgb(hex_value) Convert a hexadecimal color value to a 3-tuple of integers suitable for use in an rgb() triplet specifying that color.
rgb_to_hex(rgb_triplet) : Convert a 3-tuple of integers, suitable for use in an rgb() color triplet, to a normalized hexadecimal value for that color.
hex_to_rgb(hex_value) 将十六进制颜色值转换为适合在指定该颜色的 rgb() 三元组中使用的 3 元组整数。
rgb_to_hex(rgb_triplet) ：将适合在 rgb() 颜色三元组中使用的三元组整数转换为该颜色的标准化十六进制值。
回答by spacedentist
import re
def hex_to_int_color(v):
return tuple(int(i,16) for i in re.match(
r'^#?([0-9a-f]{2})([0-9a-f]{2})([0-9a-f]{2})$', v,
flags=re.IGNORECASE).groups())
def int_to_hex_color(v):
return '#%02x%02x%02x' % v
回答by ecik
Trying to be pythonic:
试图成为pythonic：
>>> rgbstr='aabbcc'
>>> tuple(ord(c) for c in rgbstr.decode('hex'))
(170, 187, 204)
>>> tuple(map(ord, rgbstr.decode('hex'))
(170, 187, 204)
and
和
>>> rgb=(12,50,100)
>>> "".join(map(chr, rgb)).encode('hex')
'0c3264'
回答by tsvikas
with matplotlib
使用matplotlib
matplotlib uses RGB tuples with values between 0 and 1:
matplotlib 使用值介于 0 和 1 之间的 RGB 元组：
from matplotlib.colors import hex2color, rgb2hex
hex_color = '#00ff00'
rgb_color = hex2color(hex_color)
hex_color_again = rgb2hex(rgb_color)
both rgb_colorand hex_colorare in a format acceptable by matplotlib.
二者rgb_color并hex_color处于由格式可接受matplotlib。
with webcolors
与webcolors
html uses RGB tuples with values between 0 and 255.
html 使用值在 0 到 255 之间的 RGB 元组。
you can convert between them with the module webcolors, using the functions hex_to_rgb, rgb_to_hex
您可以使用模块 webcolors 在它们之间进行转换，使用函数hex_to_rgb，rgb_to_hex
回答by Elias Zamaria
I found a simple way:
我找到了一个简单的方法：
red, green, blue = bytes.fromhex("aabbcc")
回答by Dilawar
Here you go. I use it to convert color to graphviz color format in #RGBAformat with prefix=#.
干得好。我用它的颜色转换成graphviz的色彩格式#RGBA与格式prefix=#。
def rgba_hex( color, prefix = '0x' ):
if len( color ) == 3:
color = color + (255,)
hexColor = prefix + ''.join( [ '%02x' % x for x in color ] )
return hexColor
USAGE:
用法：
In [3]: rgba_hex( (222, 100, 34) )
Out[3]: '0xde6422ff'
In [4]: rgba_hex( (0,255,255) )
Out[4]: '0x00ffffff'
In [5]: rgba_hex( (0,255,255,0) )
Out[5]: '0x00ffff00'
回答by Inti
HEX to RGB tuple
HEX 到 RGB 元组
>>> tuple(bytes.fromhex('61559a'))
(97, 85, 154)
RGB tuple to HEX
RGB 元组到 HEX
>>> bytes((97, 85, 154)).hex()
'61559a'
No imports needed!
无需进口！
What is this magic?!
这是什么魔法？！
Since bytes objects are sequences of integers (akin to a tuple), for a bytes object b, b[0] will be an integer, while b[0:1] will be a bytes object of length 1
...
The representation of bytes objects uses the literal format (b'...') since it is often more useful than e.g. bytes([46, 46, 46]). You can always convert a bytes object into a list of integers using list(b).
由于字节对象是整数序列（类似于元组），对于字节对象 b，b[0] 将是一个整数，而 b[0:1] 将是一个长度为 1 的字节对象
...
字节对象的表示使用文字格式 (b'...')，因为它通常比例如 bytes([46, 46, 46]) 更有用。您始终可以使用 list(b) 将字节对象转换为整数列表。
Source: https://docs.python.org/3/library/stdtypes.html#bytes-objects
来源：https: //docs.python.org/3/library/stdtypes.html#bytes-objects
