Python 如何从 URL 中提取文件名并在其中添加一个单词？
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How to extract a filename from a URL & append a word to it?
提问by deadlock
I have the following url:
我有以下网址：
url = http://photographs.500px.com/kyle/09-09-201315-47-571378756077.jpg
网址 = http://photographs.500px.com/kyle/09-09-201315-47-571378756077.jpg
I would like to extract the file name in this url: 09-09-201315-47-571378756077.jpg
我想提取这个网址中的文件名：09-09-201315-47-571378756077.jpg
Once I get this file name, I'm going to save it with this name to the Desktop.
获得此文件名后，我将使用此名称将其保存到桌面。
filename = **extracted file name from the url**
download_photo = urllib.urlretrieve(url, "/home/ubuntu/Desktop/%s.jpg" % (filename))
After this, I'm going to resize the photo, once that is done, I've going to save the resized version and append the word "_small" to the end of the filename.
在此之后，我将调整照片大小，完成后，我将保存调整后的版本并将“_small”一词附加到文件名的末尾。
downloadedphoto = Image.open("/home/ubuntu/Desktop/%s.jpg" % (filename))
resize_downloadedphoto = downloadedphoto.resize.((300, 300), Image.ANTIALIAS)
resize_downloadedphoto.save("/home/ubuntu/Desktop/%s.jpg" % (filename + _small))
From this, what I am trying to achieve is to get two files, the original photo with the original name, then the resized photo with the modified name. Like so:
由此，我想要实现的是获取两个文件，原始名称的原始照片，然后是修改后名称的调整大小的照片。像这样：
09-09-201315-47-571378756077.jpg
09-09-201315-47-571378756077.jpg
09-09-201315-47-571378756077_small.jpg
09-09-201315-47-571378756077_small.jpg
How can I go about doing this?
我该怎么做呢？
采纳答案by Ofir Israel
You can use urllib.parse.urlparsewith os.path.basename:
你可以用urllib.parse.urlparse与os.path.basename：
import os
from urllib.parse import urlparse
url = "http://photographs.500px.com/kyle/09-09-201315-47-571378756077.jpg"
a = urlparse(url)
print(a.path) # Output: /kyle/09-09-201315-47-571378756077.jpg
print(os.path.basename(a.path)) # Output: 09-09-201315-47-571378756077.jpg
回答by RickyA
filename = url[url.rfind("/")+1:]
filename_small = filename.replace(".", "_small.")
maybe use ".jpg" in the last case since a . can also be in the filename.
也许在最后一种情况下使用“.jpg”，因为 . 也可以在文件名中。
回答by Moj
Python split url to find image name and extension
helps you to extract the image name. to append name :
帮助您提取图像名称。附加名称：
imageName = '09-09-201315-47-571378756077'
new_name = '{0}_small.jpg'.format(imageName)
回答by Bryan
You could just split the url by "/" and retrieve the last member of the list:
您可以通过“/”分割网址并检索列表的最后一个成员：
url = "http://photographs.500px.com/kyle/09-09-201315-47-571378756077.jpg"
filename = url.split("/")[-1]
#09-09-201315-47-571378756077.jpg
Then use replaceto change the ending:
然后使用replace更改结尾：
small_jpg = filename.replace(".jpg", "_small.jpg")
#09-09-201315-47-571378756077_small.jpg
回答by P i
os.path.basename(url)
os.path.basename(url)
Why try harder?
为什么要更努力？
In [1]: os.path.basename("https://foo.com/bar.html")
Out[1]: 'bar.html'
In [2]: os.path.basename("https://foo.com/bar")
Out[2]: 'bar'
In [3]: os.path.basename("https://foo.com/")
Out[3]: ''
In [4]: os.path.basename("https://foo.com")
Out[4]: 'foo.com'
回答by Tactopoda
Sometimes there is a query string:
有时有一个查询字符串：
filename = url.split("/")[-1].split("?")[0]
new_filename = filename.replace(".jpg", "_small.jpg")
回答by Boris
Use urllib.parse.urlparseto get just the path part of the URL, and then use pathlib.Pathon that path to get the filename:
用于urllib.parse.urlparse仅获取URL的路径部分，然后pathlib.Path在该路径上使用以获取文件名：
from urllib.parse import urlparse
from pathlib import Path
url = "http://example.com/some/long/path/a_filename.jpg?some_query_params=true&some_more=true#and-an-anchor"
a = urlparse(url)
a.path # '/some/long/path/a_filename.jpg'
Path(a.path).name # 'a_filename.jpg'
