Python 3.4 用户输入
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Python 3.4 User Input
提问by jahrich
I want to write a small script to tell me if the bass level is OK or not from user input.
我想写一个小脚本来告诉我用户输入的低音水平是否正常。
I am just learning user input, and this is what I have so far:
我只是在学习用户输入，这就是我目前所拥有的：
def crisp():
bass = input("Enter bass level on a scale of 1 to 5>>")
print ("Bass level is at") + bass
if bass >=4:
print ("Bass is crisp")
elif bass < 4:
print ("Bass is not so crisp")
采纳答案by Ben Morris
I really don't see a problem here, but just a simple program that does this and only this would be as so:
我真的没有看到这里有问题，但只是一个简单的程序来执行此操作，并且仅此而已：
a=1
while a==1:
try:
bass = input('Enter Bass Level: ')
print('Bass level is at ' + str(bass))
if bass >=4:
print("Bass is crisp")
elif bass < 4:
print('Bass is not so crisp')
a=0
except ValueError:
print('Invalid Entry')
a=1
Not much difference with a function:
与函数没有太大区别：
def Bass():
a=1
while a==0:
try:
bass = input('Enter Bass Level: ')
print('Bass level is at ' + str(bass))
if int(bass) >=4:
print("Bass is crisp")
elif bass < 4:
print('Bass is not so crisp')
a=0
except ValueError:
print('Invalid Entry')
a=1
回答by Malik Brahimi
Convert to an integer:
转换为整数：
bass = int(input("Enter bass level on a scale of 1 to 5>>"))
回答by A.J. Uppal
When you take in input()through the built-in function, it takes input as a string.
当您input()通过内置函数接收时，它将输入作为字符串。
>>> x = input('Input: ')
Input: 1
>>> x
"1"
Instead, cast int()to your input():
相反，投射int()到您的input()：
>>> x = int(input('Input: '))
Input: 1
>>> x
1
Otherwise, in your code, you are checking if "4" == 4:, which is never true.
否则，在您的代码中，您正在检查if "4" == 4:，这永远不会正确。
Thus, here is your edited code:
因此，这是您编辑的代码：
def crisp():
bass = int(input("Enter bass level on a scale of 1 to 5>>"))
print ("Bass level is at") + bass
if bass >=4:
print ("Bass is crisp")
elif bass < 4:
print ("Bass is not so crisp")
