Python如何去除小数点？
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Python how to remove decimal?
提问by Robo
I've found some other topics on this but I couldn't get it to work. Please pardon my naivety with Python.
我在这方面找到了一些其他主题，但我无法让它发挥作用。请原谅我对 Python 的天真。
Berekening1 = 8.5
Berekening2 = 8.1+4.8
Berekening3 = 8*10
Berekening4 = 3
x = Berekening1 * Berekening2 * Berekening3 + Berekening4
print "Het antwoord van de berekening is:",
round(x); print x,
print "."
I want xto be an integer. How do I do that? I tried both intand round.
我想x成为一个整数。我怎么做？我尝试了int和round。
Anyone also have an idea on how to remove the "space" between xand "." at the end when code is executed?
任何人也有关于如何删除x和“。”之间的“空格”的想法。最后什么时候执行代码？
回答by Martijn Pieters
The round()function cannot alter the xvariable in place, as numbers are immutable. Instead, the rounded result is returned, which your code ignores.
该round()函数不能x就地改变变量，因为数字是不可变的。相反，将返回舍入结果，您的代码将忽略该结果。
Store the result back in x:
将结果存储回x：
x = round(x)
This will give you a floating point number rounded to the nearest whole number.
这将为您提供一个四舍五入到最接近的整数的浮点数。
Alternatively, use x = int(x), which gives you an integer number, but floorsthat number (removes the decimal portion regardless if it is closer to the next whole number or not).
可替代地，使用x = int(x)，它给你的整数，但地板该号码（无论去除小数部分，如果它更接近下一个整数或没有）。
回答by Padraic Cunningham
You would need to reassign x to the value of x = int(x)or you could also use str.format if you just want the output formatted:
您需要将 x 重新分配给的值，x = int(x)或者如果您只想格式化输出，也可以使用 str.format ：
print "Het antwoord van de berekening is: {:.0f}.".format(x)
int and round will exhibit different behaviour, if you have anything >= 5 after the decimal point then intwill floor but round will round up, if you want to actually use round you might want to combine the two:
int 和 round 将表现出不同的行为，如果小数点后有 >= 5 的任何内容，int则将向下取整，但 round 将向上取整，如果您想实际使用 round，您可能希望将两者结合起来：
In [7]: x = round(1.5)
In [8]: x
Out[8]: 2.0
In [9]: int(x)
Out[9]: 2
Or again combine with str.format:
或者再次结合str.format：
In [10]: print "Het antwoord van de berekening is: {:.0f}".format(round(1.5))
Het antwoord van de berekening is: 2
回答by aryaman
For just removing decimal part of an integer(eg- 45.55 to 45), you can try using trunc()method with math library, just like this-
对于仅删除整数的小数部分（例如- 45.55 到 45），您可以尝试使用trunc()带有数学库的方法，就像这样-
import math
i=45.55
i=math.trunc(i)
print(i)
Output will be- 45, trunc() method doesn't rounds off the integer to the nearest whole number, it justs cuts off the decimal portion.
输出将是- 45，trunc() 方法不会将整数四舍五入到最接近的整数，它只是截断小数部分。
Or if you want to round off then you can use the round()method.
或者，如果您想四舍五入，则可以使用该round()方法。
