xcode 为 println 连接混合类型
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Concatenate mixed types for println
提问by kmiklas
I am trying to concatenate a string and an integer, and log to the console using println.
我正在尝试连接一个字符串和一个整数，并使用 .log 登录到控制台println。
println("Load number: " + webViewLoads)
webViewLoads is type 'Int'. As I'm mixing two types here, there is no surprise that I'm getting an error:Could not find an overload for 'println' that accepts the supplied arguments.
webViewLoads 是“Int”类型。由于我在这里混合了两种类型，因此出现错误也就不足为奇了：Could not find an overload for 'println' that accepts the supplied arguments.
So, I tried casting webViewLoads asa string:
println("Load: " + webViewLoads as String)
所以，我尝试将 webViewLoads 转换as为字符串： println("Load: " + webViewLoads as String)
Grr.. Error still thrown.
Grr .. 错误仍然抛出。
How can I make this simple little concatenation work?
我怎样才能让这个简单的小串联工作？
回答by Mick MacCallum
You have a couple of options. You can create a new String from the Int and concatenate it, or you can use string interpolation.
你有几个选择。您可以从 Int 创建一个新的 String 并将其连接起来，或者您可以使用字符串插值。
println("Load number: " + String(webViewLoads))
println("Load number: \(webViewLoads)")
回答by PREMKUMAR
Check below code:
检查以下代码：
let string1 = "This is"
let intValue = 45
var appendString = "\(string1) \(intValue)"
println("APPEND STRING:\(appendString)")
回答by Greg A
I don't think this was mentioned, but this worked for me:
我认为没有提到这一点，但这对我有用：
println("Frame Width: " + String(stringInterpolationSegment: frameWidth))
(frameWidth is: var frameWidth = self.frame.width)
（frameWidth 为：var frameWidth = self.frame.width）
