PHP 将日期格式 Ymd 转换为 mdY
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PHP Convert Date format Y-m-d to m-d-Y
提问by user1563221
I want to make my date format in Month-Date-Year. Current format is Year-Month-Date. How do I do that in PHP?
我想让我的日期格式为Month-Date-Year. 当前格式为Year-Month-Date. 我如何在 PHP 中做到这一点？
回答by underscore
$date = "08/01/2013";
$your_date = date("m-d-y", strtotime($date));
I hope my answer is useful :)
我希望我的回答有用:)
回答by Taz
$originalDate = "2013-01-08";
$newDate = date("m-d-Y", strtotime($originalDate));
回答by Taz
You can use strtotime()to parse the date. This literally took me one Google Searchto figure this out.
您可以使用strtotime()来解析日期。从字面上看，我花了一个谷歌搜索来弄清楚这一点。
$given = "2013-01-08";
$parseit = date("m-d-Y", strtotime($given));
And then you can echo it something like this:
然后你可以像这样回显它：
echo $parseit;
回答by OrangE
echo date('m-d-Y', time());
echo date('m-d-Y', time());
For more information see PHP's date documentation.
有关更多信息，请参阅PHP 的日期文档。
回答by Sree
Try this.
尝试这个。
date('m-d-y', strtotime('2012-12-31'));
or
或者
$d = new DateTime('2012-12-31');
echo $d->format('m-d-y');
回答by Frank He
Refer to these two functions:
参考这两个函数：
For example (you need to update format)
例如（您需要更新格式）
$date = DateTime::createFromFormat('j-M-Y', '15-Feb-2009');
echo $date->format('Y-m-d');
回答by DWright
You can use strtotime()to get your string back into a time variable. Then use date()to format the time to your required format.
您可以使用strtotime()将字符串恢复为时间变量。然后使用date()将时间格式化为您所需的格式。
回答by anuj arora
Just use
只需使用
date("m-d-Y");
This will output your in Month-Date-Year.
这将输出您的 in Month-Date-Year.
回答by kennypu
$date = date("m-d-Y",strtotime($yourdate));
