如何上传带有用户名，密码，多个文件上传的HTML表单，然后使用PHP处理它？
时间：2020-03-06 14:45:55 来源:igfitidea点击:
如何从单个html表单发布用户名，密码和多个二进制文件并使用php处理它？我不允许使用ajax。
解决方案
我们应该使用$ _FILESsuperglobal和move_uploaded_file()函数查看哪些文件已成功上传，并将它们移至最终位置(以防万一)。
$ _POST`超级全局将包含提交的用户名和密码。
首先，请查看PHP.net上的这些页面
- 文件上传信息
move_uploaded_file
但是，为了让我们入门，这里有几个存根文件。
uploadForm.html
<html>
<body>
<form action="processStuff.php" enctype="multipart/form-data" method="POST">
username: <input type="text" name="username" />
password: <input type="password" name="password" />
<p>
<input type="file" name="uploadFile[]" /><br />
<input type="file" name="uploadFile[]" /><br />
<input type="file" name="uploadFile[]" /><br />
<!-- Add as many of these as you want -->
</p>
<p>
<input type="submit" />
</p>
</form>
</body>
</html>
processStuff.php
<pre>
<?php
echo '<h2>Username & password</h2>'
echo "Username: {$_POST['username']}\nPassword: {$_POST['password']}";
echo '<hr />';
echo '<h2>Uploaded files</h2>'
foreach($_FILES['uploadFile']['tmp_name'] as $i => $tempUploadPath) {
if (empty($tempUploadPath)) {
// this <input type="file" /> was "blank"... no file selected
} else {
// a file was uploaded
echo '<strong>A file named "', $_FILES['uploadFile']['name'][$i], "\" was uploaded</strong>\n";
echo "\ttemporarily stored at: ", $tempUploadPath, "\n";
echo "\tmime type: ", $_FILES['uploadFile']['type'][$i], "\n";
echo "\tsize: ", $_FILES['uploadFile']['size'][$i], " bytes\n";
echo "\terror code",
((empty($_FILES['uploadFile']['size'][$i])
? '<em>no errror</em>'
: $_FILES['uploadFile']['size'][$i])),
"\n\n";
// do something useful with the uploaded file
// access it via $tempUploadPath and use move_uploaded_file() to move
// it out of the temp path before you manipulate it in any way!!!!!
// see http://us3.php.net/features.file-upload
// and http://us3.php.net/manual/en/function.move-uploaded-file.php
}
}
?>
</pre>
HTML文件显示了如何设置<form>的enctype，第二个表单显示了如何访问提交的用户名和密码，以及最后如何循环访问每个上载的文件。
如前所述，我们必须尽快移动文件。它们已上传到临时位置，除非我们处理它们，否则系统将删除它们。因此，请先将它们移到某个地方，然后再执行我们需要的操作。
帮忙这有帮助
阿林
