Python - 将一串数字转换为一个 int 列表
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Python - converting a string of numbers into a list of int
提问by Bart M
I have a string of numbers, something like:
我有一串数字，例如：
example_string = '0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11'
I would like to convert this into a list:
我想将其转换为列表：
example_list = [0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11]
I tried something like:
我试过类似的东西：
for i in example_string:
example_list.append(int(example_string[i]))
But this obviously does not work, as the string contains spaces and commas. However, removing them is not an option, as numbers like '19' would be converted to 1 and 9. Could you please help me with this?
但这显然不起作用，因为字符串包含空格和逗号。但是，删除它们不是一种选择，因为像“19”这样的数字会被转换为 1 和 9。你能帮我解决这个问题吗？
回答by Martijn Pieters
Split on commas, then map to integers:
用逗号分割，然后映射到整数：
map(int, example_string.split(','))
Or use a list comprehension:
或者使用列表理解：
[int(s) for s in example_string.split(',')]
The latter works better on Python 3 if you want a list result.
如果您想要列表结果，后者在 Python 3 上效果更好。
This works because int()tolerates whitespace:
这是有效的，因为int()容忍空格：
>>> example_string = '0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11'
>>> map(int, example_string.split(',')) # Python 2, in Python 3 returns iterator object
[0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11]
>>> [int(s) for s in example_string.split(',')]
[0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11]
Splitting on justa comma also is more tolerant of variable input; it doesn't matter if 0, 1 or 10 spaces are used between values.
仅在逗号上拆分也更能容忍变量输入；值之间是否使用 0、1 或 10 个空格都没有关系。
回答by lucemia
it should work
它应该工作
example_string = '0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11'
example_list = [int(k) for k in example_string.split(',')]
回答by lejlot
You can also use list comprehension on splitted string
您还可以对拆分的字符串使用列表理解
[ int(x) for x in example_string.split(',') ]
回答by Charles JOUBERT
Try this :
尝试这个 ：
import re
[int(s) for s in re.split('[\s,]+',example_string)]
回答by hendrik
I guess the dirtiest solution is this:
我想最肮脏的解决方案是这样的：
list(eval('0, 0, 0, 11, 0, 0, 0, 11'))
回答by Rohit Singh
number_string = '0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11'
number_string = number_string.split(',')
number_string = [int(i) for i in number_string]
