xcode 如何在iOS中将数据字符串转换为json对象和字符串？
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How to convert data string to json object and string in iOS?
提问by Rajneesh
How to convert string to JSON object or JSON array in iOS? my JSON string Like That.
如何在 iOS 中将字符串转换为 JSON 对象或 JSON 数组？我的 JSON 字符串就像那样。
{"Data": [{"ID":"1","Name":"Raj"},{"ID":"2","Name":"Rajneesh"}]}
I want to get ID or Name from this string please help me if anyone now this.
我想从此字符串中获取 ID 或名称，如果现在有人请帮助我。
Thank You.
谢谢你。
I try below code but print null
我尝试下面的代码但打印空
NSString *JsonString=@"{"Data": [{"ID":"1","Name":"Raj"},{"ID":"2","Name":"Rajneesh"}]}";
NSData *objectData = [JsonString dataUsingEncoding:NSUTF8StringEncoding];
NSDictionary *json = [NSJSONSerialization JSONObjectWithData:objectData options:0 error:&error];
NSArray* array = [json objectForKey:@"Data"];
NSLog(@"Print Array %@",array);
回答by Kalpesh
Use this
用这个
NSString *str=@"{\"Data\": [{\"ID\":\"1\",\"Name\":\"Raj\"},{\"ID\":\"2\",\"Name\":\"Rajneesh\"}]}";
NSMutableDictionary *dict=[NSJSONSerialization JSONObjectWithData:[str dataUsingEncoding:NSUTF8StringEncoding] options:kNilOptions error:nil];
NSMutableArray *dataArr=[dict valueForKey:@"Data"];
for (NSDictionary *userData in dataArr) {
NSLog(@"Id:%@ Name:%@",[userData valueForKey:@"ID"],[userData valueForKey:@"Name"]);
}
回答by Lalit Kumar
Always Remember that when there are { } curly brackets, it means it is Dictionary and when [ ] this, means Array
永远记住，当有 { } 大括号时，表示它是 Dictionary 而当 [ ] this 时，表示 Array
NSURL *url=[NSURL URLWithString:@"Your JSON URL"];
NSData *data = [[NSData alloc] initWithContentsOfURL:url];
NSMutableDictionary *json = [NSJSONSerialization JSONObjectWithData:data options:kNilOptions error:nil];
NSArray *array = json[@"Data"];
for(NSMutableDictionary *dic in array)
{
NSLog(@"%@",dic[@"ID"]); // give 1 & 2
NSLog(@"%@",dic[@"Name"]); // Raj and Rajneesh
}
回答by Retro
This is not the correct JSON string which can be parsed by Objective c, get string from encoder and you will get a valid string, other then that for JSON to Dictionary conversion is simple in iOS as its natively supported.
这不是可以由 Objective c 解析的正确 JSON 字符串，从编码器获取字符串，您将获得一个有效字符串，除此之外，对于 JSON 到字典的转换在 iOS 中很简单，因为它本机支持。
NSData *data = [strJSON dataUsingEncoding:NSUTF8StringEncoding];
NSDictionary *jsonResponse = [NSJSONSerialization JSONObjectWithData:data
options:kNilOptions
error:&error];
