C++ 拆分一个句子，以便将每个单词添加到数组项中
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原文地址: http://stackoverflow.com/questions/26424871/
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split a sentence so that adds each word in an array item
提问by Lion King
I have a sentence, I want split the sentence so that adds each word in an array item.
I have done the following code but it still wrong.
我有一个句子，我想拆分这个句子，以便将每个单词添加到一个数组项中。
我已经完成了以下代码，但它仍然是错误的。
string str = "Welcome to the computer world.";
string strWords[5];
short counter = 0;
for(short i=0;i<str.length();i++){
strWords[counter] = str[i];
if(str[i] == ' '){
counter++;
}
}
回答by Marco A.
I'm answering since you should learn from your mistakes: just use the +=string operator and your code will work:
我正在回答，因为您应该从错误中吸取教训：只需使用+=字符串运算符，您的代码就会起作用：
// strWords[counter] = str[i]; <- change this
strWords[counter] += str[i]; <- to this
to remove the spaces (if you don't want to append them) just change the order of the space check, something like:
要删除空格（如果您不想附加它们）只需更改空格检查的顺序，例如：
for (short i = 0; i<str.length(); i++){
if (str[i] == ' ')
counter++;
else
strWords[counter] += str[i];
}
anyway I'm suggesting to use the duplicate link Split a string in C++?too
无论如何，我建议使用重复链接在 C++ 中拆分字符串？也
回答by Gunther Van Butsele
Very ugly way to do it, @Cyber has linked to the best answer. But here's your "corrected" version:
非常丑陋的方法，@Cyber 已链接到最佳答案。但这是您的“更正”版本：
string str = "Welcome to the computer world.";
string strWords[5];
short counter = 0;
for(short i=0;i<str.length();i++){
if(str[i] == ' '){
counter++;
i++;
}
strWords[counter] += str[i];
}
回答by Rudolfs Bundulis
As mentioned in the comments, there are a lot of more convenient ways to split a string (strtok, std functionality, etc.), but if we talk about your sample, you should not assign the 'str[i]' but append it, since it is a single character that you want to append to the current word like this:
正如评论中提到的，有很多更方便的方法来拆分字符串（strtok，std 功能等），但是如果我们谈论您的示例，您不应该分配 'str[i]' 而是附加它，因为它是一个单个字符，您希望像这样附加到当前单词中：
string str = "Welcome to the computer world.";
string strWords[5];
short counter = 0;
for(short i=0;i<str.length();i++){
if(str[i] == ' ' && !strWords[counter].empty()){
counter++;
}
else {
strWords[counter] += str[i];
}
}
But this will work only on the given input data, since you can access the array strWordsoutside bounds if you have more than five words. Consider using a following code:
但这仅适用于给定的输入数据，因为strWords如果您有五个以上的单词，您可以在边界之外访问数组。考虑使用以下代码：
string str = "Welcome to the computer world.";
vector<string> strWords;
string currentWord;
for(short i=0;i<str.length();i++){
if(str[i] == ' ' && !currentWord.empty()){
strWords.push_back(currentWord);
currentWord.clear();
}
else {
currentWord += str[i];
}
}
UPDATE
更新
Since I assume you are new to C++, here is the demonstration of the space issue you have (if you only use the addition operator):
由于我假设您是 C++ 的新手，这里是您遇到的空间问题的演示（如果您只使用加法运算符）：
#include <string>
#include <iostream>
using namespace std;
int main(int argc, char** argv)
{
string str = "Welcome to the computer world.";
string strWords[5];
short counter = 0;
for(short i=0;i<str.length();i++){
strWords[counter] += str[i]; // Append fixed
if(str[i] == ' '){
counter++;
}
}
for(short i=0;i<5;i++){
cout << strWords[i] << "(" << strWords[i].size() << ")" << endl;
}
return 0;
}
Result:
结果：
