bash 如何通过管道 grep 输出粘贴输入？
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How to pipe grep output to paste input?
提问by Chylomicron
I basically want to take the line that is under the word "LOAD" in filename1, and make it the second column in a new file, where the first column comes from filename2. (This is being done inside a loop, but I think that's irrelevant.)
我基本上想取filename1中“LOAD”一词下的行，并将其作为新文件中的第二列，其中第一列来自filename2。（这是在循环内完成的，但我认为这无关紧要。）
So if I have
所以如果我有
grep -A 1 LOAD filename1 >> temp
paste filename2 temp >> filename3
rm temp
Is there a way to do that in one command, with no temp file? Something like
有没有办法在没有临时文件的情况下在一个命令中做到这一点？就像是
grep -A 1 LOAD filename1 | paste filename2 "grep output" >> filename3
采纳答案by anubhava
You can use process substitutioninstead of using a temporary file:
您可以使用进程替换而不是使用临时文件：
paste filename2 <(grep -A 1 LOAD filename1) >> filename3
回答by dermen
grep -A 1 LOAD filename1.txt | paste filename2.txt /dev/stdin >> filename3.txt
回答by Ken
You can use '-' in command line to represent input from pipe
您可以在命令行中使用“-”来表示来自管道的输入
grep -A 1 LOAD filename1.txt | paste filename2.txt - >> filename3.txt
