通过 bash 脚本从“时间”命令获取值
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get values from 'time' command via bash script
提问by Derek
I want to run some executables with the time command
我想用 time 命令运行一些可执行文件
time myexec -args
How can I store only the time output to a variable in bash? Thats the only part I care about for this script, not the output of the executable. Is there a way to get that value, or will I have to parse the text of the entire command?
如何仅将时间输出存储到 bash 中的变量？这是我关心这个脚本的唯一部分，而不是可执行文件的输出。有没有办法获得该值，还是我必须解析整个命令的文本？
采纳答案by Derek
Actually, I found this as well - How to store a substring of the output of "time" function in bash script
实际上，我也发现了这一点 - How to store a substring of the output of "time" function in bash script
Probably closer to what I was looking for
可能更接近我想要的
回答by Paused until further notice.
See BashFAQ/032.
参见BashFAQ/032。
All output (stdout, stderr and time) captured in a variable:
time在变量中捕获的所有输出（stdout、stderr 和）：
var=$( { time myexec -args; } 2>&1 )
Output to stdout and stderr go to their normal places:
输出到 stdout 和 stderr 到它们的正常位置：
exec 3>&1 4>&2
var=$( { time myexec -args 1>&3 2>&4; } 2>&1 ) # Captures time only.
exec 3>&- 4>&-
回答by chris
Something like this?
像这样的东西？
TIME="$(sh -c "time myexec -args &> /dev/null" 2>&1)"
回答by karatedog
BASH has its built-in variant of time. If you do a man timeyou will find that a lot of those option listed there won't work with timecommand. The man page warns BASH users that they may use explicit path to time.
BASH 有其内置的time. 如果您执行 aman time您会发现其中列出的许多选项不适用于time命令。手册页警告 BASH 用户，他们可能会使用time.
The explicit path is /usr/bin/timeon Ubuntu, but you can find it out with $ which time.
显式路径/usr/bin/time在 Ubuntu 上，但您可以使用$ which time.
With the proper path, you can use the -for --formatoption and a lot of formatting parameters that will nicely format your result which you can store to a variable as well.
使用正确的路径，您可以使用-for--format选项和许多格式化参数，这些参数可以很好地格式化您的结果，您也可以将其存储到变量中。
STUFF_HERE=`/usr/bin/time -f %E sleep 1 2>&1`
STUFF_HERE=`/usr/bin/time -f %E sleep 1 2>&1`
