C# 拆分字符串,在一行中转换 ToList<int>()
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Split string, convert ToList<int>() in one line
提问by uzay95
I have a string that has numbers
我有一个带有数字的字符串
string sNumbers = "1,2,3,4,5";
I can split it then convert it to List<int>
我可以拆分它然后将其转换为 List<int>
sNumbers.Split( new[] { ',' } ).ToList<int>();
How can I convert string array to integer list?
So that I'll be able to convert string[]to IEnumerable
如何将字符串数组转换为整数列表?这样我就可以转换string[]为IEnumerable
采纳答案by mqp
var numbers = sNumbers.Split(',').Select(Int32.Parse).ToList();
回答by Joze
You can also do it this way without the need of Linq:
您也可以在不需要 Linq 的情况下这样做:
List<int> numbers = new List<int>( Array.ConvertAll(sNumbers.Split(','), int.Parse) );
// Uses Linq
var numbers = Array.ConvertAll(sNumbers.Split(','), int.Parse).ToList();
回答by yuxio
Joze's way also need LINQ, ToList()is in System.Linqnamespace.
Joze 的方式也需要 LINQ,ToList()是在System.Linq命名空间中。
You can convert Array to List without Linq by passing the array to List constructor:
通过将数组传递给 List 构造函数,您可以在不使用 Linq 的情况下将 Array 转换为 List:
List<int> numbers = new List<int>( Array.ConvertAll(sNumbers.Split(','), int.Parse) );
回答by HyoJin KIM
On Unity3d, int.Parsedoesn't work well. So I use like bellow.
在 Unity3d 上,int.Parse效果不佳。所以我使用如下。
List<int> intList = new List<int>( Array.ConvertAll(sNumbers.Split(','),
new Converter<string, int>((s)=>{return Convert.ToInt32(s);}) ) );
Hope this help for Unity3d Users.
希望这对 Unity3d 用户有所帮助。
回答by Pcodea Xonos
also you can use this Extension method
您也可以使用此扩展方法
public static List<int> SplitToIntList(this string list, char separator = ',')
{
return list.Split(separator).Select(Int32.Parse).ToList();
}
usage:
用法:
var numberListString = "1, 2, 3, 4";
List<int> numberList = numberListString.SplitToIntList(',');
回答by Carlos Toledo
My problem was similar but with the inconvenience that sometimes the string contains letters (sometimes empty).
我的问题很相似,但有时字符串包含字母(有时是空的),这给我带来了不便。
string sNumbers = "1,2,hh,3,4,x,5";
Trying to follow Pcode Xonos Extension Method:
尝试遵循 Pcode Xonos 扩展方法:
public static List<int> SplitToIntList(this string list, char separator = ',')
{
int result = 0;
return (from s in list.Split(',')
let isint = int.TryParse(s, out result)
let val = result
where isint
select val).ToList();
}
回答by Mukesh Kalgude
It is also possible to int array to direct assign value.
也可以通过 int 数组直接赋值。
like this
像这样
int[] numbers = sNumbers.Split(',').Select(Int32.Parse).ToArray();
回答by Charanjot
You can use this:
你可以使用这个:
List<Int32> sNumberslst = sNumbers.Split(',').ConvertIntoIntList();
回答by Adrian Filip
You can use new C# 6.0 Language Features:
您可以使用新的 C# 6.0 语言功能:
- replace delegate
(s) => { return Convert.ToInt32(s); }with corresponding method groupConvert.ToInt32 - replace redundant constructor call:
new Converter<string, int>(Convert.ToInt32)with:Convert.ToInt32
(s) => { return Convert.ToInt32(s); }用相应的方法组替换委托Convert.ToInt32- 将多余的构造函数调用替换
new Converter<string, int>(Convert.ToInt32)为:Convert.ToInt32
The result will be:
结果将是:
var intList = new List<int>(Array.ConvertAll(sNumbers.Split(','), Convert.ToInt32));
回答by aozogul
Better use int.TryParseto avoid exceptions;
更好地使用int.TryParse以避免异常;
var numbers = sNumbers
.Split(',')
.Where(x => int.TryParse(x, out _))
.Select(int.Parse)
.ToList();

