php 如何使用php删除json响应中的反斜杠(“\”)?
声明:本页面是StackOverFlow热门问题的中英对照翻译,遵循CC BY-SA 4.0协议,如果您需要使用它,必须同样遵循CC BY-SA许可,注明原文地址和作者信息,同时你必须将它归于原作者(不是我):StackOverFlow
原文地址: http://stackoverflow.com/questions/14209052/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
how remove the backslash ("\") in the json response using php?
提问by user1957012
I try to add a row of mysql query into JSON whit php. I use this code:
我尝试将一行 mysql 查询添加到 JSON whit php 中。我使用这个代码:
public function lugaresCercanos($lng, $lat, $distance){
$result=mysql_query("SELECT nombre, distancia FROM Lugar ORDER BY distancia ASC");
$info=array();
while($row = mysql_fetch_array($result,MYSQL_ASSOC)){
array_push($info,$row);
}
return json_encode($info);
This returns a JSONObject, but I'm not sure.
这将返回一个 JSONObject,但我不确定。
class resultado_final {
public $logstatus = "";
public $lugares_cercanos = "";}
$result_final = new resultado_final();
if($db->login($usuario,$passw)){
$result_final->logstatus = "0";}else{
$result_final->logstatus = "1";}
$result_final->lugares_cercanos = $lista;
echo json_encode($result_final);
This code print this:
此代码打印此:
{"logstatus":"1","lugares_cercanos":"[{\"nombre\":\"Rio Amazonas\",\"distancia\":\"5119.000\"},{\"nombre\":\"Swissotel \",\"distancia\":\"5823.000\"},{\"nombre\":\"Laguna de Yaguarcocha\",\"distancia\":\"71797.000\"}]"}
why the rows of the query are separated by backslashes? how remove the backslashes? Thanks alot!
为什么查询的行用反斜杠分隔?如何删除反斜杠?非常感谢!
回答by Nick Perkins
The \ is to escape the quotes (") that are part of the response.
\ 用于转义作为响应一部分的引号 (")。
Use stripslashes()to strip these out.
使用stripslashes()剥离出来这些。
When a string wrapped in quotes contains quotes, they have to be escaped. The escape character in php is \.
当包含在引号中的字符串包含引号时,必须对其进行转义。php 中的转义字符是\.
回答by sk8terboi87 ツ
Try
尝试
json_encode($arr, JSON_UNESCAPED_SLASHES);
or
或者
echo str_replace('\/','/',json_encode($mydatas));
(if unescape doesn't work) http://php.net/manual/en/function.json-encode.php
(如果 unescape 不起作用) http://php.net/manual/en/function.json-encode.php
回答by Ignacio Vazquez-Abrams
Stop double-encoding your data. Put everything together in one large structure and then encode only that.
停止对您的数据进行双重编码。将所有内容放在一个大型结构中,然后仅对其进行编码。
回答by user1957012
Thanks, I resolve it.
谢谢,我解决了。
$info=array();
while($row = mysql_fetch_array($result,MYSQL_ASSOC)){
array_push($info,$row);
}
$info;
$result_final->lugares_cercanos = $info;
Print this:
打印这个:
{"logstatus":"1","lugares_cercanos":[{"nombre":"Rio Amazonas","distancia":"5119.000"}{"nombre":"Swissotel Quito","distancia":"5823.000"}{"nombre":"Laguna de Yaguarcocha","distancia":"71797.000"}]}
回答by Devner
If anyone wants to remove the backslashes and also pretty print the JSON data, the following can be used:
如果有人想删除反斜杠并漂亮地打印 JSON 数据,可以使用以下内容:
json_encode($my_array, JSON_UNESCAPED_UNICODE | JSON_PRETTY_PRINT);

