python 如何在python中发送xml-rpc请求？
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How to send a xml-rpc request in python?
提问by John Jiang
I was just wondering, how would I be able to send a xml-rpcrequest in python? I know you can use xmlrpclib, but how do I send out a request in xmlto access a function?
我只是想知道，我如何能够xml-rpc在 python 中发送请求？我知道您可以使用xmlrpclib，但是如何发出请求xml以访问某个功能？
I would like to see the xmlresponse.
我想看看xml回应。
So basically I would like to send the following as my request to the server:
所以基本上我想将以下内容作为我的请求发送到服务器：
<?xml version="1.0"?>
<methodCall>
<methodName>print</methodName>
<params>
<param>
<value><string>Hello World!</string></value>
</param>
</params>
</methodCall>
and get back the response
并得到回复
回答by Eli Bendersky
Here's a simple XML-RPC client in Python:
这是一个用 Python 编写的简单 XML-RPC 客户端：
import xmlrpclib
s = xmlrpclib.ServerProxy('http://localhost:8000')
print s.myfunction(2, 4)
Works with this server:
与此服务器一起使用：
from SimpleXMLRPCServer import SimpleXMLRPCServer
from SimpleXMLRPCServer import SimpleXMLRPCRequestHandler
# Restrict to a particular path.
class RequestHandler(SimpleXMLRPCRequestHandler):
rpc_paths = ('/RPC2',)
# Create server
server = SimpleXMLRPCServer(("localhost", 8000),
requestHandler=RequestHandler)
def myfunction(x, y):
status = 1
result = [5, 6, [4, 5]]
return (status, result)
server.register_function(myfunction)
# Run the server's main loop
server.serve_forever()
To access the guts of xmlrpclib, i.e. looking at the raw XML requests and so on, look up the xmlrpclib.Transportclass in the documentation.
要访问 的内容xmlrpclib，即查看原始 XML 请求等，请xmlrpclib.Transport在文档中查找该类。
回答by Nicholas Clarke
I have pared down the source code in xmlrpc.clientto a minimum required to send a xml rpc request (as I was interested in trying to port the functionality). It returns the response XML.
我已将xmlrpc.client 中的源代码减少到发送 xml rpc 请求所需的最低限度（因为我对尝试移植功能感兴趣）。它返回响应 XML。
Server:
服务器：
from xmlrpc.server import SimpleXMLRPCServer
def is_even(n):
return n%2 == 0
server = SimpleXMLRPCServer(("localhost", 8000))
print("Listening on port 8000...")
server.register_function(is_even, "is_even")
server.serve_forever()
Client:
客户：
import http.client
request_body = b"<?xml version='1.0'?>\n<methodCall>\n<methodName>is_even</methodName>\n<params>\n<param>\n<value><int>2</int></value>\n</param>\n</params>\n</methodCall>\n"
connection = http.client.HTTPConnection('localhost:8000')
connection.putrequest('POST', '/')
connection.putheader('Content-Type', 'text/xml')
connection.putheader('User-Agent', 'Python-xmlrpc/3.5')
connection.putheader("Content-Length", str(len(request_body)))
connection.endheaders(request_body)
print(connection.getresponse().read())
回答by Alex Martelli
What do you mean by "get around"? xmlrpclibis thenormal way to write an XML-RPC client in python. Just look at the sources(or copy them to your own module and add printstatements!-) if you want to know the details of how things are done.
你说的“绕道”是什么意思？ xmlrpclib是在 python 中编写 XML-RPC 客户端的正常方法。如果您想知道事情是如何完成的细节，只需查看源代码（或将它们复制到您自己的模块并添加print语句！-）。
