Python 写入我的临时文件的权限被拒绝
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Permission Denied To Write To My Temporary File
提问by Mack
I am attempting to create and write to a temporary file on Windows OS using Python. I have used the Python module tempfileto create a temporary file.
我正在尝试使用 Python 在 Windows 操作系统上创建和写入临时文件。我使用 Python 模块tempfile创建了一个临时文件。
But when I go to write that temporary file I get an error Permission Denied. Am I not allowed to write to temporary files?! Am I doing something wrong? If I want to create and write to a temporary file how should should I do it in Python? I want to create a temporary file in the temp directory for security purposes and not locally (in the dir the .exe is executing).
但是当我去写那个临时文件时，我得到了一个错误Permission Denied。我不允许写入临时文件吗？！难道我做错了什么？如果我想创建并写入一个临时文件，我应该如何在 Python 中做到这一点？为了安全起见，我想在临时目录中创建一个临时文件，而不是在本地（在 .exe 正在执行的目录中）。
IOError: [Errno 13] Permission denied: 'c:\\users\\blah~1\\appdata\\local\\temp\\tmpiwz8qw'
IOError: [Errno 13] Permission denied: 'c:\\users\\blah~1\\appdata\\local\\temp\\tmpiwz8qw'
temp = tempfile.NamedTemporaryFile().name
f = open(temp, 'w') # error occurs on this line
采纳答案by paxdiablo
NamedTemporaryFileactually creates and opensthe file for you, there's no need for you to open it again for writing. In fact, the Python docsstate:
NamedTemporaryFile实际上为您创建并打开文件，您无需再次打开它进行写入。实际上，Python 文档指出：
Whether the name can be used to open the file a second time, while the named temporary file is still open, varies across platforms (it can be so used on Unix; it cannot on Windows NT or later).
在命名的临时文件仍处于打开状态时，是否可以使用该名称再次打开该文件，因平台而异（在 Unix 上可以如此使用；在 Windows NT 或更高版本上则不能）。
That's why you're getting your permission error. What you're probably after is:
这就是您收到许可错误的原因。你可能追求的是：
f = tempfile.NamedTemporaryFile(mode='w') # open file
temp = f.name # get name (if needed)
回答by Vidyesh Ranade
Use the delete parameter as below:
使用删除参数如下：
tmpf = NamedTemporaryFile(delete=False)
But then you need to manually delete the temporary file once you are done with it.
但是，一旦完成，您需要手动删除临时文件。
tmpf.close()
os.unlink(tmpf.name)
Reference for bug: https://github.com/bravoserver/bravo/issues/111
错误参考：https: //github.com/bravoserver/bravo/issues/111
regards, Vidyesh
问候， 维迪耶什
回答by Richie Zubiri
Permission was denied because the file is Open during line 2 of your code.
权限被拒绝，因为文件在代码的第 2 行中处于打开状态。
close it with f.close() first then you can start writing on your tempfile
先用 f.close() 关闭它，然后你就可以开始在你的临时文件上写了
回答by Erik Aronesty
Consider using os.path.join(tempfile.gettempdir(), os.urandom(24).hex())instead. It's reliable, cross-platform, and the only caveat is that it doesn't work on FAT partitions.
考虑os.path.join(tempfile.gettempdir(), os.urandom(24).hex())改用。它是可靠的、跨平台的，唯一需要注意的是它不适用于 FAT 分区。
NamedTemporaryFile has a number of issues, not the least of which is that it can fail to create files because of a permission error, fail to detect the permission error, and then loop millions of times, hanging your program and your filesystem.
NamedTemporaryFile 有很多问题，其中最重要的是它可能会因为权限错误而无法创建文件，无法检测权限错误，然后循环数百万次，挂起您的程序和文件系统。
