bash Linux find 和 grep 命令一起使用
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Linux find and grep command together
提问by user3307574
I am trying to find a command or create a Linux script that can do this two comands and list the otuput
我试图找到一个命令或创建一个 Linux 脚本来执行这两个命令并列出 otuput
find . -name '*bills*' -print
this prints all the files
这将打印所有文件
./may/batch_bills_123.log
./april/batch_bills_456.log
..
from this result I want to do a grep for a word I do this manually right now
从这个结果我想为一个词做一个 grep 我现在手动做这个
grep 'put' ./may/batch_bill_123.log
and get
并得到
sftp > put oldnet_1234.lst
I would hope to get the file name and its match.
我希望获得文件名及其匹配项。
./may/batch_bills_123.log sftp > put oldnet_1234.lst
..
..
and so on...
any ideas?
有任何想法吗？
回答by BMW
You are looking for -Hoption in gnu grep.
您正在-Hgnu grep中寻找选项。
find . -name '*bills*' -exec grep -H "put" {} \;
Here is the explanation
这是解释
-H, --with-filename
Print the filename for each match.
回答by Reinstate Monica Please
Now that the question is clearer, you can just do this in one grep
现在问题更清楚了，您可以在一个grep 中完成此操作
grep -R --include "*bills*" "put" .
With relevant flags
带有相关标志
-R, -r, --recursive
Read all files under each directory, recursively; this is
equivalent to the -d recurse option.
--include=GLOB
Search only files whose base name matches GLOB (using wildcard
matching as described under --exclude).
回答by Dalin
Or maybe even easier
或者甚至更容易
grep -R put **/*bills*
The **glob syntax means "any depth of directories". It will work in Zsh, and I think recent versions of Bash too.
该**水珠语法手段“目录中的任何深度”。它可以在 Zsh 中工作，我认为 Bash 的最新版本也是如此。
