Python (Help) TypeError: 'str' 对象不能被解释为整数
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(Help) TypeError: 'str' object cannot be interpreted as an integer
提问by AMVGod Z
Traceback (most recent call last):
File "<pyshell#0>", line 1, in <module>
get_odd_palindrome_at('racecar', 3)
File "C:\Users\musar\Documents\University\Courses\Python\Assignment 2\palindromes.py", line 48, in get_odd_palindrome_at
for i in range(string[index:]):
TypeError: 'str' object cannot be interpreted as an integer
I want to use the value index refers to but how do I do that?
我想使用引用的价值指数，但我该怎么做？
回答by vincent-lg
It seems from your error than the 'index' variable is a string, not an int. You could convert it using int().
从你的错误看来，'index' 变量是一个字符串，而不是一个整数。您可以使用 int() 转换它。
index = int(index)
for i in range(string[index:]):
Now, string[index:] will also be an string. So you would need to convert that too:
现在， string[index:] 也将是一个字符串。所以你也需要转换它：
>>> string = "5"
>>> range(string)
Traceback (most recent call last):
File "<stdin>", line 1, in <module>
TypeError: range() integer end argument expected, got str.
>>> range(int(string))
[0, 1, 2, 3, 4]
>>>
That's assuming that string[index:] only contains a number. If that's not always the case, you can do something like:
那是假设 string[index:] 只包含一个数字。如果情况并非总是如此，您可以执行以下操作：
# 'index' contains only numbers
index = int(index)
number = string[index:]
if number.isdigit():
number = int(number)
for i in range(number):
From the Wikipedia article on Python:
Python uses duck typing and has typed objects but untyped variable names. Type constraints are not checked at compile time; rather, operations on an object may fail, signifying that the given object is not of a suitable type. Despite being dynamically typed, Python is strongly typed, forbidding operations that are not well-defined (for example, adding a number to a string) rather than silently attempting to make sense of them.
Python 使用鸭子类型并具有类型化的对象但未类型化的变量名称。编译时不检查类型约束；相反，对对象的操作可能会失败，这表明给定的对象不是合适的类型。尽管是动态类型的，但 Python 是强类型的，禁止未明确定义的操作（例如，向字符串添加数字），而不是默默地尝试理解它们。
In this case, you try to pass a string to range(). This function waits for a number (a positive integer, as it is). That's why you need to convert your string to int. You could actually do a bit more of checking, depending on your needs. Python cares for types.
在这种情况下，您尝试将字符串传递给 range()。这个函数等待一个数字（一个正整数，因为它是）。这就是为什么您需要将字符串转换为 int 的原因。你实际上可以做更多的检查，这取决于你的需要。Python关心类型。
HTH,
哈，
