Java 如何将 Android 应用程序连接到 Web 服务器
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How to connect Android app to web server
提问by Trapper Davis
I am working on designing an Android application for my senior design project. The application will need to be able to connect to a web server. The web server is just a locally hosted Apache web server on a personal computer. The application will need to download a makeshift software update to the phone/application.
我正在为我的高级设计项目设计一个 Android 应用程序。该应用程序需要能够连接到 Web 服务器。Web 服务器只是个人计算机上本地托管的 Apache Web 服务器。该应用程序需要将临时软件更新下载到手机/应用程序。
At this point in the design, I have the login page and home page built. The problem I am having is how to connect to a web server from the app. My professor has also requested that from the login page, if the proper username and password have been entered, that these credentials will also access the web server. I am also questioning if this is even possible. Any advice will be greatly received.
在设计的这一点上，我已经构建了登录页面和主页。我遇到的问题是如何从应用程序连接到 Web 服务器。我的教授还要求从登录页面，如果输入了正确的用户名和密码，这些凭据也将访问网络服务器。我也在质疑这是否可能。任何建议都会很受欢迎。
Thanks - Please let me know if this question needs more info or is not clear enough to answer.
谢谢 - 如果这个问题需要更多信息或不够清楚无法回答，请告诉我。
回答by Wol Lamoseu
If you want REST API you can refer here
如果你想要 REST API，你可以参考这里
Make an HTTP request with androidSending HTTP Post Request with Android
使用 android发出HTTP 请求 使用 Android发送 HTTP Post 请求
Else if you want hybrid application you can refer here
否则，如果你想要混合应用程序，你可以参考这里
回答by vinod
The best way use volley library
使用凌空库的最佳方式
http://www.androidhive.info/2014/05/android-working-with-volley-library-1/
http://www.androidhive.info/2014/05/android-working-with-volley-library-1/
回答by Bethan
It's very interesting to do the connections of the android to the remote server, very anxiety. Below link will help you max for your need.
做android到远程服务器的连接很有意思，很着急。下面的链接将帮助您最大限度地满足您的需求。
Android Connect with Php Mysql
Android Connection using servlets
And If you wanna connect the server from the android device by using HttpUrlConnection then follow the below code.
如果您想使用 HttpUrlConnection 从 android 设备连接服务器，请按照以下代码操作。
private static JSONObject get(Context ctx, String sUrl) {
HttpURLConnection connection = null;
try {
URL url = new URL(sUrl);
connection = (HttpURLConnection) url.openConnection();
connection.setRequestProperty("Content-Type", "application/json");
connection.setRequestProperty("Accept", "application/json");
connection.setRequestProperty("Authorization",
"Basic " + encodedAuthentication);
connection.setRequestProperty("Accept-Charset", "utf-8,*");
Log.d("Get-Request", url.toString());
try {
BufferedReader bufferedReader = new BufferedReader(
new InputStreamReader(connection.getInputStream()));
StringBuilder stringBuilder = new StringBuilder();
String line;
while ((line = bufferedReader.readLine()) != null) {
stringBuilder.append(line).append("\n");
}
bufferedReader.close();
Log.d("Get-Response", stringBuilder.toString());
return new JSONObject(stringBuilder.toString());
} finally {
connection.disconnect();
}
} catch (Exception e) {
Log.e("ERROR", e.getMessage(), e);
return null;
}
}
private static String buildSanitizedRequest(String url,
Map<String, String> mapOfStrings) {
Uri.Builder uriBuilder = new Uri.Builder();
uriBuilder.encodedPath(url);
if (mapOfStrings != null) {
for (Map.Entry<String, String> entry : mapOfStrings.entrySet()) {
Log.d("buildSanitizedRequest", "key: " + entry.getKey()
+ " value: " + entry.getValue());
uriBuilder.appendQueryParameter(entry.getKey(),
entry.getValue());
}
}
String uriString;
try {
uriString = uriBuilder.build().toString(); // May throw an
// UnsupportedOperationException
} catch (Exception e) {
Log.e("Exception", "Exception" + e);
}
return uriBuilder.build().toString();
}
And Json calling part should look like,
而 Json 调用部分应该看起来像，
public static JSONObject exampleGetMethod(Context ctx, String sUrl, String username, String password) throws JSONException, IOException {
Map<String, String> request = new HashMap<String, String>();
request.put("username", username);
request.put("password",password);
sUrl = sUrl + "yourApiName";
return get(ctx, buildSanitizedRequest(sUrl, request));
}
