Linux Shell命令在目录模式中查找文件
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/4581203/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Shell command to find files in a directory pattern
提问by Grant Unwin
With a shell command i need to list all files on my server in the following directory pattern:
使用 shell 命令，我需要以以下目录模式列出服务器上的所有文件：
/home/*/public_html/images/*.php
/home/*/public_html/images/*.php
Theres a few an its taking a long time to do this manually. I really have no idea when it comes to these commands.
手动执行此操作需要很长时间。当涉及到这些命令时，我真的不知道。
采纳答案by jmort253
Shell Script:
外壳脚本：
find /home/*/public_html/images -iname "*php" -exec echo {} \;
You can then change the -exec command to do whatever actions you want to the returned files. In this case, we echo them, but you could easily perform other actions as well.
然后，您可以更改 -exec 命令以对返回的文件执行任何操作。在这种情况下，我们会回应它们，但您也可以轻松地执行其他操作。
回答by Matthew Flaschen
Use the PHP globfunction
使用 PHP glob函数
glob('/home/*/public_html/images/*.php')
It will return an array of the matching path strings. You can also just use:
它将返回匹配路径字符串的数组。你也可以只使用：
ls /home/*/public_html/images/*.php
or:
或者：
for i in /tmp/*/public_html/images/*.php;
do
some_command "$i"
done
from the shell.
从外壳。
回答by moinudin
Let bash expand the files for you and use lsto list them:
让 bash 为您展开文件并用于ls列出它们：
ls /home/*/public_html/images/*.php
Example output:
示例输出：
/home/grant/public_html/images/bar.php
/home/grant/public_html/images/foo.php
/home/marcog/public_html/images/helloworld.php
回答by karthik m
find /path/to/directory/. -path "*/match/this/path/*" -type f -name "*.php"
