bash grep -v 文件中的多个字符串
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grep -v multiple strings from file
提问by Asaf S
I have 2 files:
我有2个文件：
- file1
- 文件 1
string list:
字符串列表：
ben
john
eric
- file2
- 文件 2
few rows:
几行：
ben when to school
my mother went out
the dog is big
john has FB
eric is nice guy
expoted file :
暴露的文件：
my mother went out
the dog is big
I would like to use grep -vand remove the rows that contains the strings from list.
我想使用grep -v并删除包含列表中字符串的行。
this is the idea but the wrong command :
这是想法，但错误的命令：
grep -v `cat file2` file1 > out
Thanks
谢谢
Asaf
阿萨夫
回答by anubhava
Using a file for patterns:
使用模式文件：
grep -v -f "file2" file1 > out
or else you can do:
否则你可以这样做：
grep -v -e "string1" -e "string2" file1
回答by saeedgnu
If I understand the question correctly, 4 matched lines should be removed one by one, and a single grep can't do it unless you define a REGEXP containing those 4 lines, which is tricky
如果我正确理解了问题，则应将 4 行匹配的行一一删除，除非您定义包含这 4 行的 REGEXP，否则单个 grep 无法执行，这很棘手
But this script should do it
但是这个脚本应该可以做到
cp file2 out
cat file1 | while read STR ; do
LINE="`grep \"$STR\" file2`"
sed -i "/^$LINE$/d" out
done
cat out
