Python：字典列表
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Python: List of lists to dictionary
提问by JustAskingThings
I have a file which contains data in the following format: please note this is an example of what it looks like, the actual file contains more than 2 rows
我有一个包含以下格式数据的文件：请注意这是一个示例，实际文件包含超过 2 行
1 30 5
2 64 4
I read in the file, convert the text to integers, and store them into a list. This is done with the following code:
我读入文件，将文本转换为整数，然后将它们存储到列表中。这是通过以下代码完成的：
file = open("dataFile.txt", "r")
items = []
for line in file:
line = map(int,line.split()) #convert the text data to integers
items.append(line) #add text data to list
The current format for the list looks like:
列表的当前格式如下所示：
[[1, 30, 5], [2, 64, 4]]
I need to turn my list of lists into a dictionary. How would one go about doing this?
我需要将我的列表列表变成字典。怎么做呢？
Dictionary key should be the first element
字典键应该是第一个元素
采纳答案by TessellatingHeckler
I'm going to play guess-what-you-want, and assume the first numbers in each row are in fact some kind of sequential identifier, and you want
我要玩猜你想要什么，并假设每一行中的第一个数字实际上是某种顺序标识符，并且你想要
1 30 5
2 64 4
to become
成为
1 : [30, 5]
2 : [64, 4]
so...
所以...
with open("dataFile.txt") as dataFile:
items = {}
for line in dataFile:
line = map(int, line.split()) #convert the text data to integers
key, value = line[0], line[1:]
items[key] = value
(and I've changed the name of filebecause file()is already a builtin function in Python, and reusing that name for something else is bad form).
（我已经更改了名称，file因为file()它已经是 Python 中的一个内置函数，而将这个名称重用于其他东西是不好的形式）。
Or you could use a dictionary comprehension instead, starting with your items list:
或者您可以改用字典理解，从您的项目列表开始：
itemDict = {item[0]: item[1:] for item in items}
回答by Patrick Yu
Assuming you want your dictionary key to be the 1st element of the list, here is an implementation:
假设您希望您的字典键是列表的第一个元素，这里是一个实现：
list = [[1, 30, 5], [2, 64, 4]]
dict = {}
for l2 in list:
dict[l2[0]] = l2[1:]
It works by iterating through list, and the sub-list l2. Then, I take the 1st element of l2and assign it as a key to dict, and then take the rest of the elements of l2and put it as the value.
它通过迭代list和子列表来工作l2。然后，我取 的第一个元素l2并将其分配为 的键dict，然后取其余的元素l2并将其作为值。
The result is the finished dictionary {1: [30, 5], 2: [64, 4]}
结果是完成的字典 {1: [30, 5], 2: [64, 4]}
