java 获取响应的 Spring restTemplate 问题
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Spring restTemplate issue in getting response
提问by Muhammad Imran Tariq
My rest server is generating response when I called it with rest client software. When I call it with resttemplatecode mentioned above, then server generates response(print logs) but resttemplatedoes nothing(no next line executes after call) and prints internal error.
当我使用 rest 客户端软件调用它时，我的 rest 服务器正在生成响应。当我用resttemplate上面提到的代码调用它时，服务器生成响应（打印日志）但resttemplate不执行任何操作（调用后不执行下一行）并打印内部错误。
This is the method in my server
这是我服务器中的方法
@ResponseBody
public ResponseEntity<Map<String, Object>> name(){......
...
return new ResponseEntity<Map<String, Object>>(messagebody, HttpStatus.OK);
}
This is the way I am calling it through restTemplate
这是我通过 restTemplate 调用它的方式
ResponseEntity<Map> response1 = restTemplate.getForEntity(finalUrl.toString(), Map.class);
回答by Sergey Yamshchikov
Try to use ParameterizedTypeReferenceinstead of wildcarded Map. It should looks like this.
尝试使用ParameterizedTypeReference而不是通配符Map。它应该是这样的。
ParameterizedTypeReference<Map<String, Object>> typeRef = new ParameterizedTypeReference<Map<String, Object>>() {};
ResponseEntity<Map<String, Object>> response = restTemplate.exchange(finalUrl.toString(), HttpMethod.GET, null, typeRef);
回答by user3193801
this is a example that works for me
这是一个对我有用的例子
@RequestMapping(value = "/getParametros/{instancia}", method = RequestMethod.GET, produces = MediaType.TEXT_PLAIN_VALUE)
public ResponseEntity<String> getParametros(@PathVariable String instancia)
{
LOG.debug("REST. Obteniendo parametros del servidor " + instancia);
Map<String, String> mapa = parametrosService.getProperties(instancia);
HttpHeaders headers = new HttpHeaders();
headers.add("Content-Type", "application/json; charset=UTF-8");
headers.add("X-Fsl-Location", "/");
headers.add("X-Fsl-Response-Code", "302");
ObjectMapper mapper = new ObjectMapper();
String s = "";
try
{
s = mapper.writeValueAsString(mapa);
} catch (JsonProcessingException e)
{
LOG.error("NO SE PUEDE MAPEAR A JSON");
}
if (mapa == null)
return new ResponseEntity<String>(HttpStatus.BAD_REQUEST);
return new ResponseEntity<String>(s, headers, HttpStatus.OK);
}
回答by Abhishek Singh
you can Catch the HttpStatusCodeException from which you can get response in String . below code works for me.
您可以捕获 HttpStatusCodeException ，您可以从中获得 String 的响应。下面的代码对我有用。
restTemplate.postForObject( url, jsonRequest, ResponseData.class );
catch( HttpStatusCodeException codeException )
{
String payload = codeException.getResponseBodyAsString();
System.out.println( payload );
}
