bash sed 删除除字母和 ' 之外的所有字符
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sed to remove all characters except letters and '
提问by Jakob
I am using this sed command to strip documents of all their (for me) unnecessary characters.
我正在使用这个 sed 命令来去除所有（对我来说）不必要的字符的文档。
sed 's/[^a-zA-Z]/ /g'
However after mining my data a bit I realized a pretty basic mistake:
not including 'cuts all my don'ts into don ts, which sucks.
然而，在稍微挖掘我的数据之后，我意识到一个非常基本的错误：不包括'将我所有的don'ts 切割成don ts，这很糟糕。
So i want to include 'in my regex. I'm still new to this kind of "coding" if I may call it that way, so excuse my newbie mistake or even better, explain it to me!
所以我想包含'在我的正则表达式中。如果我可以这样称呼它，我对这种“编码”仍然是新手，所以请原谅我的新手错误，甚至更好，向我解释一下！
sed 's/[^a-zA-Z']/ /g'this obviously doesn't work
sed 's/[^a-zA-Z']/ /g'这显然不起作用
sed 's/[^a-zA-Z\']/ /g'however this doesn't either, I thought \escapes the '?
sed 's/[^a-zA-Z\']/ /g'然而这也不是，我认为\逃脱了'？
回答by Jean-Fran?ois Fabre
Good old double-quotes in action to protect the single quote without any need of escaping:
很好的旧双引号可以保护单引号而无需转义：
sed "s/[^a-zA-Z']/ /g" <<< "don't ... do this"
gives:
给出：
don't do this
EDIT: your code seems to replace non-letters by space, but your question states otherwise, so I'm giving you the other version, to remove all non-letters/spaces and multiple occurrences of spaces as well (2nd expression).
编辑：你的代码似乎用空格替换了非字母，但你的问题另有说明，所以我给你另一个版本，删除所有非字母/空格和多次出现的空格（第二个表达式）。
sed -e "s/[^ a-zA-Z']//g" -e 's/ \+/ /' <<< "don't ... do this"
result:
结果：
don't do this
EDIT2: alternate solution to be able to keep single quotes (courtesy of Sundeep):
EDIT2：能够保留单引号的替代解决方案（由 Sundeep 提供）：
`'s/[^ a-zA-Z\x27]//g'`
Note: I first tried to escape single quotes following the solutions tested hereand none using single quotes worked for me (always prompting for a line continuation) so I came up with those alternatives.
注意：我首先尝试按照此处测试的解决方案转义单引号，但没有使用单引号对我有用（总是提示行继续），所以我想出了这些替代方案。
回答by Joel Griffiths
You can also use tr -cd "'[:alnum:] "
你也可以使用 tr -cd "'[:alnum:] "
$ echo "some string '*'@'#'%^ without special chars except '" | tr -cd "'[:alnum:]"
$ somestring''''withoutspecialcharsexcept'
If you want the spaces:
如果你想要空格：
echo "some string '*'@'#'%^ without special chars except '" | tr -cd "'[:alnum:] "
some string '''' without special chars except '
