bash sed 替换所有字符直到第一个空格
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Sed replace all characters until first space
提问by nervosol
I am trying to replace some paths in config file. To do that I am trying to use sed.
我正在尝试替换配置文件中的一些路径。为此，我正在尝试使用 sed。
My file looks something like that:
我的文件看起来像这样：
-Djava.util.logging.config.file=/tmp/tmp/tmp/config bla.bla
I want to replace /tmp/tmp/tmp/configand keep bla.bla untouched.
According to http://regexpal.com/and http://regexr.com?362qcI should use
我想替换/tmp/tmp/tmp/config并保持 bla.bla 不变。根据http://regexpal.com/和http://regexr.com?362qc我应该使用
sed -e 's/logging.config.file=[^\s]+/logging\.config\.file\=\/new/g' file
sed -e 's/logging.config.file=[^\s]+/logging\.config\.file\=\/new/g' file
But it doesnt work.
但它不起作用。
采纳答案by fedorqui 'SO stop harming'
This will replace /tmp/tmp/...with aaa:
这将替换/tmp/tmp/...为aaa：
$ sed 's/\(.*=\)[^ ]* \(.*\)/ aaa /g' <<< "-Djava.util.logging.config.file=/tmp/tmp/tmp/config bla.bla"
-Djava.util.logging.config.file= aaa bla.bla
It "saves" anything up to =in \1. Then fetches everything up to an space. Finally "saves" the rest of the string in \2.
它“保存”任何东西直到=in \1。然后将所有内容提取到一个空间。最后将字符串的其余部分“保存”在\2.
The replacement is done by echoing \1+ "new string" + \2.
替换是通过 echo \1+ "new string" + 完成的\2。
回答by choroba
\sis not supported by sed. Also, the +must be backslashed to get its special meaning. I would also backslash the dots to prevent them from matching anything:
\s不支持sed。此外，+必须反斜杠才能获得其特殊含义。我还会反斜杠点以防止它们匹配任何内容：
sed -e 's/logging\.config\.file=[^[:space:]]\+/logging\.config\.file\=\/new/g'
or, shorter
或者，更短
sed -e 's%\(logging\.config\.file=\)[^[:space:]]\+%/new%g'
