Python Regex，re.sub，替换模式的多个部分？
声明：本页面是StackOverFlow热门问题的中英对照翻译，遵循CC BY-SA 4.0协议，如果您需要使用它，必须同样遵循CC BY-SA许可，注明原文地址和作者信息，同时你必须将它归于原作者（不是我）：StackOverFlow
原文地址: http://stackoverflow.com/questions/3519487/
Warning: these are provided under cc-by-sa 4.0 license. You are free to use/share it, But you must attribute it to the original authors (not me):
StackOverFlow
Python Regex, re.sub, replacing multiple parts of pattern?
提问by Rick
I can't seem to find a good resource on this.. I am trying to do a simple re.place
我似乎找不到这方面的好资源..我正在尝试做一个简单的 re.place
I want to replace the part where its (.*?), but can't figure out the syntax on how to do this.. I know how to do it in PHP, so I've been messing around with what I think it could be based on that (which is why it has the $1 but I know that isn't correct in python).. I would appreciate if anyone can show the proper syntax, I'm not asking specifics for any certain string, just how I can replace something like this, or if it had more than 1 () area.. thanks
我想替换它的 (.*?) 部分，但无法弄清楚如何做到这一点的语法..我知道如何在 PHP 中做到这一点，所以我一直在搞乱我的想法可能基于此（这就是为什么它有 $1，但我知道这在 python 中是不正确的）。如果有人可以显示正确的语法，我将不胜感激，我不是在询问任何特定字符串的细节，只是如何我可以替换这样的东西，或者如果它有超过 1 () 个区域..谢谢
originalstring = 'fksf var:asfkj;'
pattern = '.*?var:(.*?);'
replacement_string='' + 'test'
replaced = re.sub(re.compile(pattern, re.MULTILINE), replacement_string, originalstring)
采纳答案by Umang
>>> import re
>>> originalstring = 'fksf var:asfkj;'
>>> pattern = '.*?var:(.*?);'
>>> pattern_obj = re.compile(pattern, re.MULTILINE)
>>> replacement_string="\1" + 'test'
>>> pattern_obj.sub(replacement_string, originalstring)
'asfkjtest'
Edit: The Python Docscan be pretty useful reference.
编辑：Python Docs是非常有用的参考。
回答by Rick
The python docs are online, and the one for the re module is here. http://docs.python.org/library/re.html
python 文档在线，re 模块的文档在这里。http://docs.python.org/library/re.html
To answer your question though, Python uses \1 rather than $1 to refer to matched groups.
不过，为了回答您的问题，Python 使用 \1 而不是 $1 来引用匹配的组。
回答by Daniel Kluev
>>> import re
>>> regex = re.compile(r".*?var:(.*?);")
>>> regex.sub(r"test", "fksf var:asfkj;")
'asfkjtest'
