PHP：在循环中合并数组
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PHP: Merge arrays in loop
提问by Milen
public function getCheckoutForm(){
$arr = array(
'cmd' => '_cart',
'business' => 'some@mail',
'no_shipping' => '1',
'upload' => '1',
'return' => 'url',
'cancel_return' => 'url1',
'no_note' => '1',
'currency_code' => 'url2',
'bn' => 'PP-BuyNowBF');
$cpt=1;
foreach($this->items as $item){
$arr1[] = array(
'item_number_'.$cpt.'' => $item['item_id'],
'item_name_'.$cpt.'' => $item['item_name'],
'quantity_'.$cpt.'' => $item['item_q'],
'amount_'.$cpt.'' => $item['item_price']
);
$cpt++;
}
return array_merge($arr,$arr1[0],$arr1[1]);
}
This returns array like that:
这将返回这样的数组：
Array
(
[cmd] => _cart
[business] => some@mail
[no_shipping] => 1
[upload] => 1
[return] => url1
[cancel_return] =>url2
[no_note] => 1
[currency_code] => EUR
[bn] => PP-BuyNowBF
[item_number_1] => 28
[item_name_1] => item_name_1
[quantity_1] => 1
[amount_1] => 5
[item_number_2] => 27
[item_name_2] => item_name_2
[quantity_2] => 1
[amount_2] => 30
)
The problem is that in return $arr1[0] and $arr1[1] are hardcoded. And if in loop i have more than 2 arrays, lets say 0,1,2,3 ans so on, this code won't work. Any idea? Maybe my logic is compleatly wrong...
问题是作为回报 $arr1[0] 和 $arr1[1] 是硬编码的。如果在循环中我有 2 个以上的数组，比如说 0,1,2,3 等等，这段代码将不起作用。任何的想法？也许我的逻辑是完全错误的......
回答by Cal
There's no need to create arrays in your loop - just add new keys directly to the first array:
无需在循环中创建数组 - 只需将新键直接添加到第一个数组：
public function getCheckoutForm(){
$arr = array(
'cmd' => '_cart',
'business' => 'some@mail',
'no_shipping' => '1',
'upload' => '1',
'return' => 'url',
'cancel_return' => 'url1',
'no_note' => '1',
'currency_code' => 'url2',
'bn' => 'PP-BuyNowBF'
);
$cpt=1;
foreach($this->items as $item){
$arr['item_number_'.$cpt] = $item['item_id'];
$arr['item_name_'.$cpt] = $item['item_name'];
$arr['quantity_'.$cpt] = $item['item_q'];
$arr['amount_'.$cpt] = $item['item_price'];
$cpt++;
}
return $arr;
}
回答by eagle12
I would probably do something like
我可能会做类似的事情
$count = count($arr1);
for($i=0;$i<$count;$i++){
$arr = array_merge($arr,$arr1[$i]);
}
return $arr;
回答by KingCrunch
I hope, I understood, what you mean ^^
我希望，我明白你的意思^^
foreach ($i = 0, $n = count($arr1); $i < $n; $i++) {
$arr = array_merge($arr, $arr1[$i]);
}
return $arr;
回答by AndreKR
You could do the merge in every iteration:
您可以在每次迭代中进行合并：
foreach($this->items as $item){
$temp_arr = array(
'item_number_'.$cpt.'' => $item['item_id'],
'item_name_'.$cpt.'' => $item['item_name'],
'quantity_'.$cpt.'' => $item['item_q'],
'amount_'.$cpt.'' => $item['item_price']
);
$arr = array_merge($arr,$temp_arr)
$cpt++;
}
which has the advantage that you could possibly get $temp_arrfrom a function,
它具有您可能$temp_arr从函数中获得的优势，
or just add all the elements to one array:
或者只是将所有元素添加到一个数组中：
foreach($this->items as $item){
$arr['item_number_'.$cpt.''] => $item['item_id'];
$arr['item_name_'.$cpt.''] => $item['item_name'];
$arr['quantity_'.$cpt.''] => $item['item_q'];
$arr['amount_'.$cpt.''] => $item['item_price'];
$cpt++;
}
回答by Ali sadikin
do this
做这个
$count = count($data);
$sum = 1;
$arr = [];
for($i=0;$i<$count;$i++){
$temp = $arr;
if($i == $count - 1){
$sum = 0;
}
$arr = array_merge($temp,$data[$i + $sum]);
}
return $arr;
