bash pgrep 检测重复进程
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pgrep detect duplicate processes
提问by Atomiklan
I am trying to use pgrep to first detect if a process is running and if so, determine if the process has been duplicated (run) accidentally. If so, it should it kill the duplicate processes.
我正在尝试使用 pgrep 首先检测进程是否正在运行，如果是，则确定该进程是否已被意外复制（运行）。如果是这样，它应该杀死重复的进程。
if ! pgrep -f "java" > /dev/null; then
echo "Yes its running but there may be duplicates"
< Now check for duplicates here and kill if necessary >
fi
Please help
请帮忙
* UPDATE *
* 更新 *
ps aux:
ps辅助：
debian 2521 3.8 5.4 407212 27524 pts/0 Sl 20:16 0:08 java -cp somefile.jar
Code:
代码：
if [ $(pgrep -f "somefile.jar" | wc -l) -gt 1 ]; then
kill $(pgrep -f "somefile.jar" | grep -v $(pgrep -o "somefile.jar") | awk '{printf " "}');
fi
Works but throws an error
有效但抛出错误
* UPDATE *
* 更新 *
Here is a direct paste of my code:
这是我的代码的直接粘贴：
if [ $(pgrep -f java | wc -l) -gt 1 ]; then
echo "kill $(pgrep -f java | grep -v $(pgrep -of java) | sort -n | uniq | awk '{printf " "}')";
fi
回答by iamauser
This should do :
这应该做：
#!/bin/bash
if [ $(pgrep -f java | wc -l) -gt 1 ]; then
kill $(pgrep -f java | grep -v $(pgrep -of java) | sort -n | uniq | awk '{printf " "}');
fi
pgrep -owill give you the oldest (most likely the first) java process. You want grep -vthat process and kill others.
pgrep -o将为您提供最旧的（很可能是第一个）java 进程。你想要grep -v这个过程并杀死其他人。
回答by Steve Howard
You're using the return code of pgrep, but the output might be more useful if you need to know how many.
您正在使用 pgrep 的返回码，但如果您需要知道有多少，输出可能会更有用。
HOW_MANY_JAVAS = $(pgrep -f 'java' | wc -l)
if ((HOW_MANY_JAVAS > 1)) ; then
echo 'too much Java.'
fi
回答by konsolebox
An example:
一个例子：
# Collect pids of all java processes in sorted order.
readarray -t PIDS < <(exec pgrep -f java | sort -n)
# Kill all pids except the first.
[[ ${#PIDS[@]} -gt 1 ]] && kill "${PIDS[@]:2}"
