在 C++ 中是否有内置的拆分字符串的方法？
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Is There A Built-In Way to Split Strings In C++?
提问by jimi hendrix
well is there? by string i mean std::string
有吗？字符串我的意思是 std::string
回答by heeen
Here's a perl-style split function I use:
这是我使用的 perl 风格的拆分函数：
void split(const string& str, const string& delimiters , vector<string>& tokens)
{
// Skip delimiters at beginning.
string::size_type lastPos = str.find_first_not_of(delimiters, 0);
// Find first "non-delimiter".
string::size_type pos = str.find_first_of(delimiters, lastPos);
while (string::npos != pos || string::npos != lastPos)
{
// Found a token, add it to the vector.
tokens.push_back(str.substr(lastPos, pos - lastPos));
// Skip delimiters. Note the "not_of"
lastPos = str.find_first_not_of(delimiters, pos);
// Find next "non-delimiter"
pos = str.find_first_of(delimiters, lastPos);
}
}
回答by Martin Cote
回答by MSalters
Yup, stringstream.
是的，串流。
std::istringstream oss(std::string("This is a test string"));
std::string word;
while(oss >> word) {
std::cout << "[" << word << "] ";
}
回答by strager
STL strings
STL 字符串
You can use string iterators to do your dirty work.
您可以使用字符串迭代器来完成您的脏活。
std::string str = "hello world";
std::string::const_iterator pos = std::find(string.begin(), string.end(), ' '); // Split at ' '.
std::string left(str.begin(), pos);
std::string right(pos + 1, str.end());
// Echoes "hello|world".
std::cout << left << "|" << right << std::endl;
回答by Igor Oks
void split(string StringToSplit, string Separators)
{
size_t EndPart1 = StringToSplit.find_first_of(Separators)
string Part1 = StringToSplit.substr(0, EndPart1);
string Part2 = StringToSplit.substr(EndPart1 + 1);
}
回答by dirkgently
The answer is no. You have to break them up using one of the library functions.
答案是不。您必须使用库函数之一将它们分解。
Something I use:
我使用的东西：
std::vector<std::string> parse(std::string l, char delim)
{
std::replace(l.begin(), l.end(), delim, ' ');
std::istringstream stm(l);
std::vector<std::string> tokens;
for (;;) {
std::string word;
if (!(stm >> word)) break;
tokens.push_back(word);
}
return tokens;
}
You can also take a look at the basic_streambuf<T>::underflow()method and write a filter.
你也可以看看basic_streambuf<T>::underflow()方法，写一个过滤器。
回答by Mr.Ree
What the heck... Here's my version...
什么鬼……这是我的版本……
Note: Splitting on ("XZaaaXZ", "XZ") will give you 3 strings. 2 of those strings will be empty, and won'tbe added to theStringVector if theIncludeEmptyStrings is false.
注意：拆分 ("XZaaaXZ", "XZ") 将为您提供 3 个字符串。其中 2 个字符串将为空，如果 theIncludeEmptyStrings 为 false ，则不会添加到 StringVector。
Delimiter is notany element in the set, but rather matches that exact string.
分隔符不是集合中的任何元素，而是匹配该确切字符串。
inline void
StringSplit( vector<string> * theStringVector, /* Altered/returned value */
const string & theString,
const string & theDelimiter,
bool theIncludeEmptyStrings = false )
{
UASSERT( theStringVector, !=, (vector<string> *) NULL );
UASSERT( theDelimiter.size(), >, 0 );
size_t start = 0, end = 0, length = 0;
while ( end != string::npos )
{
end = theString.find( theDelimiter, start );
// If at end, use length=maxLength. Else use length=end-start.
length = (end == string::npos) ? string::npos : end - start;
if ( theIncludeEmptyStrings
|| ( ( length > 0 ) /* At end, end == length == string::npos */
&& ( start < theString.size() ) ) )
theStringVector -> push_back( theString.substr( start, length ) );
// If at end, use start=maxSize. Else use start=end+delimiter.
start = ( ( end > (string::npos - theDelimiter.size()) )
? string::npos : end + theDelimiter.size() );
}
}
inline vector<string>
StringSplit( const string & theString,
const string & theDelimiter,
bool theIncludeEmptyStrings = false )
{
vector<string> v;
StringSplit( & v, theString, theDelimiter, theIncludeEmptyStrings );
return v;
}
回答by Marco Kinski
There is no common way doing this.
没有通用的方法可以做到这一点。
I prefer the boost::tokenizer, its header only and easy to use.
我更喜欢boost::tokenizer，它只有标题并且易于使用。
回答by Allen Ratcliff
A fairly simple method would be to use the c_str() method of std::string to get a C-style character array, then use strtok() to tokenize the string. Not quite as eloquent as some of the other solutions listed here, but it's easy and works.
一个相当简单的方法是使用 std::string 的 c_str() 方法来获取 C 风格的字符数组，然后使用 strtok() 来标记字符串。不像这里列出的其他一些解决方案那样雄辩，但它很容易并且有效。
回答by strager
C strings
C字符串
Simply insert a \0where you wish to split. This is about as built-in as you can get with standard C functions.
只需\0在要拆分的位置插入一个。这与使用标准 C 函数可以获得的内置功能差不多。
This function splits on the first occurance of a charseparator, returning the second string.
此函数在char分隔符第一次出现时拆分，返回第二个字符串。
char *split_string(char *str, char separator) {
char *second = strchr(str, separator);
if(second == NULL)
return NULL;
*second = '##代码##';
++second;
return second;
}
